Using the least common multiple of 4 and 10, it is found that the smallest number of candies each order could have contained is 20 candies.
--------------------------------
- There are boxes of 4 candies and of 10 candies.
- Thus, the smallest possible number of equal candies on two orders in the<u> least common multiple of 4 and 10.</u>
- To find this multiple, we factor both numbers by their prime factors, thus:
4 - 10|2
2 - 5|2
1 - 5|5
1
Thus, lcm(4,10) = 2*2*5 = 20.
- The smallest possible number is 20 candies, one order with 20/4 = 5 boxes of 4 candies, and the other with 20/10 = 2 boxes of 10 candies.
A similar problem is given at brainly.com/question/24540608
An ordered pair is written as (x, y)
P(-3) = 18
The -3 is the x value and the 18 is the y value
Answer: (-3,18)
Answer:
1, 5, 2, 4, 3, 7, 6
Step-by-step explanation:
After dividing by the leading coefficient, each equation can be put into the form ...
x² + y² + ax +by +c = 0
Subtracting c and separately completing the square for x-terms and y-terms, we get ...
x² + ax + (a/2)² + y² + by + (b/2)² = -c + (a/2)² + (b/2)²
(x +a/2)² + (y +b/2)² = r² = (a/2)² + (b/2)² -c . . . . . rewrite in standard form
Ordering by the square of the radius length will match the ordering by radius length, so we just need to compute (a/2)² +(b/2)² -c for each given equation. I find it convenient to let a calculator or spreadsheet do this calculation (see attached).
In the order the equations are given, the square of the radius is ...
3, 18, 45, 23, 5, 117, 46
So the order of the equations from smallest radius to largest is ...
1, 5, 2, 4, 3, 7, 6
Answer:
x= 3, y = 5
Step-by-step explanation:
(45x -5) + (16x + 2) = 180° (because p and q are parallel )
61x = 180 therefore x = 3
(16x +2) + 26y = 180° (because it's a right angle)
we already kniw x is 3 sp just put the values in place and you will find the answer as 5.