3/8 because divide denominator by 2
Answer:
<h3>#1</h3>
- x² - 9 = 0
- x² = 9
- x = ± √9
- x = ± 3
Yes, -3 and 3 are zeroes of this polynomial
<h3>#2</h3>
<em>See attached graphs</em>
Zero's of a polynomial are the intersection of the graph with the x-axis.
They include coordinates as (x, 0), so the x-coordinates are zero's.
The attached shows the zero's.
<h3>#3</h3>
<em>See attached graphs</em>
Zero's of each polynomial are reflected in the graphs.
- () y = x² - x - 6 has zeros x = -2 and x = 3
- (ii) y = 6 - x - x² has zero's x = -3, x = 2
Answer:7m^5 - 3m^3 + 9
Step-by-step explanation: You’d have to remove the brackets, but remember that the second has to have everything multiplied by -1, because there’s a minus sign in front of the second bracket. Then you’d group like terms, then add or subtract. Here’s the step by step
6m^5 + 3 - m^3 - 4m + m^5 - 2m^3 + 4m + 6
2. 6m^5 + m^5 - 2m^3 - m^3 + 4m - 4m + 6 + 3
Subtract or add what’s needed, which would be figures with the same variable and coefficient.
3. 7m^5 - 3m^3 + 9
After this, there’s nothing you can add, since the remaining figures don’t have the same variable.
Hope it’s clear and this wasn’t that long
Answer:
4.
f(x) = (x + 2)(x + 1)(x - 3) = x^3 - 7·x - 6
a = 0 ; b = -7 ; c = -6
5.
a = -3 ∧ b = -2 ∧ c = -3
