Answer:
quantitative manipulation of the independent variable
Answer:
c=20
Step-by-step explanation:
200=10c
200/10=c
20=c
Answer:
$12.49
Step-by-step explanation:
The price right now = 0.8 * the original price
9.99 = 0.8*x
x=12.4875
x≈12.49
Sorry, I thought your problem meant that it was 20% the original price, not 20% off.
Answer:
(g+f)(x)=(2^x+x-3)^(1/2)
Step-by-step explanation:
Given
f(x)= 2^(x/2)
And
g(x)= √(x-3)
We have to find (g+f)(x)
In order to find (g+f)(x), both the functions are added and simplified.
So,
(g+f)(x)= √(x-3)+2^(x/2)
The power x/2 can be written as a product of x*(1/2)
(g+f)(x)= √(x-3)+(2)^(1/2*x)
We also know that square root dissolves into power ½
(g+f)(x)=(x-3)^(1/2)+(2)^(1/2*x)
We can see that power ½ is common in both functions so taking it out
(g+f)(x)=(x-3+2^x)^(1/2)
Arranging the terms
(g+f)(x)=(2^x+x-3)^(1/2) ..
Answer:
Exponent laws:
1. Product law

In product law if bases are same then we add their respective powers.But if bases are different we can't add their powers.
x=base, a,b,c=exponent
If x=2 and a=3, b=5 , and c=10, then

2.Product raised to a power
1. ![[x^{a}]^{c}=x^{ac}](https://tex.z-dn.net/?f=%5Bx%5E%7Ba%7D%5D%5E%7Bc%7D%3Dx%5E%7Bac%7D)
2. ![[x^{a}\times x^{b}]^{c}=[x^{a+b}]^{c}=x^{ac+bc}](https://tex.z-dn.net/?f=%5Bx%5E%7Ba%7D%5Ctimes%20x%5E%7Bb%7D%5D%5E%7Bc%7D%3D%5Bx%5E%7Ba%2Bb%7D%5D%5E%7Bc%7D%3Dx%5E%7Bac%2Bbc%7D)
If product is raised to a certain power , keeping the base same , we just multiply the powers.for example
and
![[2^{3}\times3^{2}]^{2}=[2^{3}]^2 \times[3^{2}]^{2}=2^{6}\times3^{4}](https://tex.z-dn.net/?f=%5B2%5E%7B3%7D%5Ctimes3%5E%7B2%7D%5D%5E%7B2%7D%3D%5B2%5E%7B3%7D%5D%5E2%20%5Ctimes%5B3%5E%7B2%7D%5D%5E%7B2%7D%3D2%5E%7B6%7D%5Ctimes3%5E%7B4%7D)
![[2^{3}\times2^{2}]^{2}=[2^{3+2}]^{2}=[2^{5}]^{2}=2^{10}](https://tex.z-dn.net/?f=%5B2%5E%7B3%7D%5Ctimes2%5E%7B2%7D%5D%5E%7B2%7D%3D%5B2%5E%7B3%2B2%7D%5D%5E%7B2%7D%3D%5B2%5E%7B5%7D%5D%5E%7B2%7D%3D2%5E%7B10%7D)