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3 years ago

64/7 as a mixed number

Mathematics

2 answers:

masya89 [10]3 years ago

6 0

9 and 1/7
You can just look it up on the internet.

Kruka [31]3 years ago

6 0

Answer:

Step 1 - Find Whole Number

Calculate out how many times the denominator goes into the numerator. To do that, divide 64 by 9 and keep only what is to the left of the decimal point:

64 / 9 = 7.1111 = 7

Step 2 - Find New Numerator

Multiply the answer from Step 1 by the denominator and deduct that from the original numerator.

64 - (9 x 7) = 1

Step 3 - Get Solution

Keep the original denominator and use the answers from Step 1 and Step 2 to get the answer. 64/9 as a mixed number is:

Step-by-step explanation:

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In a survey, 11 people were asked how much they spent on their child's last birthday gift. The results were roughly bell-shaped

pickupchik [31]

Answer:

The population standard deviation is not known.

90% Confidence interval by T₁₀-distribution: (38.3, 53.7).

Step-by-step explanation:

The "standard deviation" of $14 comes from a survey. In other words, the true population standard deviation is not known, and the $14 here is an estimate. Thus, find the confidence interval with the Student t-distribution. The sample size is 11. The degree of freedom is thus $11 - 1 = 10$ .

Start by finding 1/2 the width of this confidence interval. The confidence level of this interval is 90%. In other words, the area under the bell curve within this interval is 0.90. However, this curve is symmetric. As a result,

The area to the left of the lower end of the interval shall be $1/2 \cdot (1 - 0.90)= 0.05$ .
The area to the left of the upper end of the interval shall be $0.05 + 0.90 = 0.95$ .

Look up the t-score of the upper end on an inverse t-table. Focus on the entry with

a degree of freedom of 10, and
a cumulative probability of 0.95.

$t \approx 1.812$ .

This value can also be found with technology.

The formula for 1/2 the width of a confidence interval where standard deviation is unknown (only an estimate) is:

$\displaystyle t \cdot \frac{s_{n-1}}{\sqrt{n}}$ ,

where

$t$ is the t-score at the upper end of the interval,
$s_{n-1}$ is the unbiased estimate for the standard deviation, and
$n$ is the sample size.

For this confidence interval:

$t \approx 1.812$ ,
$s_{n-1} = 14$ , and
$n = 11$ .

Hence the width of the 90% confidence interval is

$\displaystyle 1.812 \times \frac{14}{\sqrt{10}} \approx 7.65$ .

The confidence interval is centered at the unbiased estimate of the population mean. The 90% confidence interval will be approximately:

$(38.3, 53.7)$ .

5 0

3 years ago

Add 14 to the quotient of 42 and 6, then double the result

PolarNik [594]

The answer is 42 why, because 42 divided by 6 equals 7 plus 14 is 21 and then you double it so it's 42.

3 0

3 years ago

What is the mean for the data set

Andrew [12]

First you would need to add up all of the data given, then divide the sum by 9 because there is 9 pieces of data. So it would be 229/9=25.4444444 repeating.

5 0

3 years ago

Read 2 more answers

Halle's mom sent her to the store to buy some peaches and plums . The total cost of the peaches was $1.88 .The plans cost zero d

VMariaS [17]

Answer:

Halle bought 6 plums from the store.

Step-by-step explanation:

Given:

total cost of the peaches = $1.88

Cost of 1 Plum = $0.33

Total Money paid = $3.86