In a class of 24 kids, for every 1 boy there are 4 girls
The only restraints on profit result from the restriction on the domain which in turn place a restriction on profit.
0≤k. Knives sold cannot be negative.
So the range of profit or p is:
p=[-500, +oo)
Profit increases as the number of knives sold increases. $200 more profit is gained by each sale of a knife.
4000=200k-500
4500=200k
k=22.5
Since k is for knives sold, it must be an integer value, so a $4000 profit is not possible. At 22, p=3900 and at 23, p=4100
y = number of days
35.50 + 18.25 y = 163.25
18.25 y = 163.25 - 35.50
18.25y = 127.75
y = 127.75 / 18.25
y = 7
so Martin has hired the machine for 8 days
( first day paid 35.50), then 7 days for 18.25
The minimum cost is achieved when 150 trees are produced giving a minimum cost of $27.5
Polynomial is an expression that involves the <em>operations of addition, subtraction, multiplication of variables.</em>
Let C represent the cost for buying and caring for n trees. Given that:
C = 0.001n² - 0.3n + 50.
The minimum cost is at dC/dn = 0, hence:
dC/dn = 0.002n - 0.3
0.002n - 0.3 = 0
0.002n = 0.3
n = 150
C(150) = 0.001(150)² - 0.3(150) + 50 = 27.5
The minimum cost is achieved when 150 trees are produced giving a minimum cost of $27.5
Find out more at: brainly.com/question/25836610
1.) Start by figuring out what the 4x3 grid would look like. In this grid, we have 12 boxes (4 x 3 = 12).
2.) Now let's calculate 25% of 12. When changing a percent to a decimal, simply move the decimal point over to the left two places. So then 25% = .25 when written as a decimal. Multiply 25 x 12. 25% of 12 equals 3.
3.) Now your grid would have 3 boxes shaded in. I put two examples of this in the attached image. However, your boxes can be shaded in anywhere in the grid, as long as only 3 of them are shaded in!