All categories

3 years ago

What is an angle that is supplementary KFA?

Mathematics

1 answer:

cestrela7 [59]3 years ago

6 0

Given:

A diagram.

To find:

An angle that is supplementary to ∠KFA.

Solution:

Supplementary angle: Two angles are called supplementary angles if they are lie on the same side of a straight line and their sum is 180 degrees.

From the given diagram, it is clear that ∠KFA lies on the intersection of lines HL and IK.

∠KFA and ∠DFA lie on the same side of a straight line IK.

∠KFA and ∠KFL lie on the same side of a straight line HL.

So, ∠DFA and ∠KFL are the angles supplementary to ∠KFA.

We need only one supplementary angle. So, we write either ∠DFA or ∠KFL.

Therefore, an angle that is supplementary to ∠KFA is ∠KFL.

You might be interested in

Write down the inequality described by "half of x is no more than six", and solve it<br>

Montano1993 [528]

X/.5 > 6
(the > has a line under it but idk how to type that lol)

5 0

3 years ago

Last week Anna received a pay check for $442.50. She noticed in the check stub that $47.30 of the money she earned had been with

Troyanec [42]

Answer:

Percentage of Taxes = 10.689 %

Step-by-step explanation:

Given that

Total earning of Anna is $442.50

The amount which is held with Taxes = $47.30

Now in terms of percentage

percentage of taxes from her total earning = $\frac{47.30}{442.50} times 100$

So % taxes = ( 0.106892) × 100

∴ Taxes percentage = 10.689 %

6 0

3 years ago

Someone please help??

Ksju [112]

Answer:

hey

Step-by-step explanation:

4 0

3 years ago

Evaluate the surface integral ModifyingBelow Integral from nothing to nothing Integral from nothing to nothing With Upper S f (x

kykrilka [37]

Parameterize $S$ by

$\vec s(u,v)=6\cos u\sin v\,\vec\imath+6\sin u\sin v\,\vec\jmath+6\cos v\,\vec k$

with $0\le u\le2\pi$ and $0\le v\le\frac\pi2$ . Take a normal vector to $S$ ,

$\dfrac{\partial\vec s}{\partial v}\times\dfrac{\partial\vec s}{\partial u}=36\cos u\sin^2v\,\vec\imath+36\sin u\sin^2v\,\vec\jmath+36\cos v\sin v\,\vec k$

which has norm

$\left\|\dfrac{\partial\vec s}{\partial v}\times\dfrac{\partial\vec s}{\partial u}\right\|=36\sin v$

Then the integral of $f(x,y,z)=x^2+y^2$ over $S$ is

$\displaystyle\iint_Sx^2+y^2\,\mathrm dS=\iint_S\left((6\cos u\sin v)^2+(6\sin u\sin v)^2\right)\left\|\frac{\partial\vec s}{\partial v}\times\frac{\partial\vec s}{\partial u}\right\|\,\mathrm du\,\mathrm dv$

$=\displaystyle36^2\int_0^{\pi/2}\int_0^{2\pi}\sin^3v\,\mathrm du\,\mathrm dv=\boxed{1728\pi}$

6 0

4 years ago

Diana can type 100 form letters

satela [25.4K]

Answer:

it will take 3 hours long

8 0

3 years ago