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3 years ago

Answer correctly= brainliest

Mathematics

1 answer:

Arturiano [62]3 years ago

4 0

Answer:

12 points/14 shots = 18 points/w shots

Step-by-step explanation:

I used the graph for game 1 and 2, and plugged in the numbers.

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Use the rules for long division to divide 724 by 9

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80 R4 or 80 with a remainder of 4

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4 years ago

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Tyree is determining the distance of a segment whose endpoints are A(–4, –2) and B(–7, –7).

PilotLPTM [1.2K]

Answer:

Tyree’s solution is inaccurate. In step 1, he substituted incorrectly.

Step-by-step explanation:

to find the distance between two point A(-4, -2) and B(-7, -7) we use the following distance formula

$d=\sqrt{(x_{2} -x_{1})^2+(y_{2}-y_{1} )^2 \\\\$

x1=-4, x2=-7

y1=-2, y2=-7

so,

$d=\sqrt{(-7-(-4))^2+(-7-(-2) )^2\\}\\\\d=\sqrt{(-7+4)^2+(-7+2)^2 }\\\\d=\sqrt{(-3)^2+(-5)^2 }\\\\\\\\d=\sqrt{9+25}\\ \\d=\sqrt{34}$

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4 years ago

For the function y = x + 4, what is the output value if 3 is the input value?

Leya [2.2K]

According to the data given above; x= 3..

y=x+4
y=3+4
y=7

7 0

3 years ago

Confirm that f and g are inverses by showing that f(g(x)) = x and g(f(x)) = x.

vekshin1

Answer:

it's b idjsnjwjsnsn

Step-by-step explanation:

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3 years ago

NO LINKS!!! Please help me with these problems

nadezda [96]

<h3>Answers:</h3>

7) Center= (-1,2) Radius= $\boldsymbol{\sqrt{8}}$ Equation: $(x+1)^2+(y-2)^2 = 8$

8) Center= (3,13) Radius= 13 Equation: $(x-3)^2+(y-13)^2 = 169$

=========================================================

Explanation:

Problem 7

Let's find the distance from (-1,2) to (-3,4)

$(x_1,y_1) = (-1,2) \text{ and } (x_2, y_2) = (-3,4)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(-1-(-3))^2 + (2-4)^2}\\\\d = \sqrt{(-1+3)^2 + (2-4)^2}\\\\d = \sqrt{(2)^2 + (-2)^2}\\\\d = \sqrt{4 + 4}\\\\d = \sqrt{8}\\\\$

This is the radius because it stretches from the center to a point on the circle, so $r = \sqrt{8}$

Squaring both sides will get us $r^2 = 8$

One useful template for a circle is the equation $(x-h)^2+(y-k)^2 = r^2\\\\$

(h,k) is the center

r is the radius

Let's plug in the given center (h,k) = (-1,2) and the r^2 value we found earlier.

$(x-h)^2+(y-k)^2 = r^2\\\\(x-(-1))^2+(y-2)^2 = 8\\\\(x+1)^2+(y-2)^2 = 8\\\\$

You can confirm this by using a tool like Desmos. See below.

------------------------------------------------------------------------

Problem 8

The endpoints of the diameter are (-2,1) and (8,25)

The center is the midpoint of these endpoints.

The midpoint of the x coordinates is (-2+8)/2 = 3

The midpoint of the y coordinates is (1+25)/2 = 13

The center is (h,k) = (3,13)

Now find the distance from the center to one of the points on the circle, let's say to (8,25)

$(x_1,y_1) = (3,13) \text{ and } (x_2, y_2) = (8,25)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(3-8)^2 + (13-25)^2}\\\\d = \sqrt{(-5)^2 + (-12)^2}\\\\d = \sqrt{25 + 144}\\\\d = \sqrt{169}\\\\d = 13\\\\$

The radius is exactly 13 units.

So,

$(x-h)^2+(y-k)^2 = r^2\\\\(x-3)^2+(y-13)^2 = 13^2\\\\(x-3)^2+(y-13)^2 = 169\\\\$

is the equation of this particular circle.

Visual confirmation is shown below.

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2 years ago

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