Answer:
$138,345
Step-by-step explanation:
This is a compound decline problem, which will be solve by the compound formula:

Where
F is the future value (value of house at 2030, 14 years from 2016)
P is the present value ($245,000)
r is the rate of decline, in decimal (r = 4% = 4/100 = 0.04)
t is the time in years (2016 to 2030 is 14 years, so t = 14)
We substitute the known values and find F:

Rounding it up, it will be worth around $138,345 at 2030
Answer:
l = gt²/(2π)²
Step-by-step explanation:
if T = 2π√l/g
squaring both sides
(T)² = (2π)² × (√l/g)²
T² =4π² × l/g
T² = 4π²l/g
using cross multiplication techniqes
gT² = 4π²l
divede both sides by " 4π²"
gT²/4π² =4π²l/4π²
gT²/4π² =l
l = gT²/(2π)²
that is the final answer.
34 is the original number.
This is because 34 times 2 is 68 and 68 plus 3 is 71.