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2 years ago

2,550 gallons in 30 days i wish if you plz explain it.

Mathematics

2 answers:

alekssr [168]2 years ago

8 0

Answer:

Step-by-step explanation:

first u will div 2550 by 30 and it will 38 gallons per day or per hour

e-lub [12.9K]2 years ago

3 0

Answer:

multiply 2,550 gallons to 30 and you will have your answer

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Kristin spent $131 on shirts. Fancy shirts cost $28 and plain shirts cost $15. If she bought a total of 7 shirts then how many o

KIM [24]

Answer:

Kristin bought 5 plain shirts and 2 fancy shirts.

Hope this helps!

4 0

3 years ago

Please help. Thank you

Inessa [10]

Given:

$PQRS\sim TUVW$

In the given figure, PS=x, RS=35, UV=20, VW=25 and TW=15

To find:

The scale factor from PQRS to TUVW.

Solution:

We have,

$PQRS\sim TUVW$

We know that the corresponding sides of similar figures are proportional. The scale factor is the ratio of one side of image and corresponding side of preimage.

The scale factor is:

$k=\dfrac{VW}{RS}$

$k=\dfrac{25}{35}$

$k=\dfrac{5}{7}$

Therefore, the scale factor from PQRS to TUVW is $k=\dfrac{5}{7}$ .

6 0

3 years ago

Prove that :( 1 + 1/<img src="https://tex.z-dn.net/?f=tan%5E%7B2%7DA" id="TexFormula1" title="tan^{2}A" alt="tan^{2}A" align="ab

Aliun [14]

Answer:

See explanation

Step-by-step explanation:

Simplify left and right parts separately.

$\left(1+\dfrac{1}{\tan^2A}\right)\left(1+\dfrac{1}{\cot ^2A}\right)\\ \\=\left(1+\dfrac{1}{\frac{\sin^2A}{\cos^2A}}\right)\left(1+\dfrac{1}{\frac{\cos^2A}{\sin^2A}}\right)\\ \\=\left(1+\dfrac{\cos^2A}{\sin^2A}\right)\left(1+\dfrac{\sin^2A}{\cos^2A}\right)\\ \\=\dfrac{\sin^2A+\cos^2A}{\sin^2A}\cdot \dfrac{\cos^2A+\sin^A}{\cos^2A}\\ \\=\dfrac{1}{\sin^2A}\cdot \dfrac{1}{\cos^2A}\\ \\=\dfrac{1}{\sin^2A\cos^2A}$

<u>Right part:</u>

$\dfrac{1}{\sin^2A-\sin^4A}\\ \\=\dfrac{1}{\sin^2A(1-\sin^2A)}\\ \\=\dfrac{1}{\sin^2A\cos^2A}$

Since simplified left and right parts are the same, then the equality is true.

3 0

3 years ago

Solve b to the second power=77

zubka84 [21]

Answer:

$\large\boxed{b=\pm\sqrt{77}}$

Step-by-step explanation:

$b^2=77\iff b=\pm\sqrt{77}\\\\\text{because}\\\\(-\sqrt{77})^2=77\ \text{and} \ (\sqrt{77})^2=77$

3 0

3 years ago

4x + 1/3 y 2 what is the value of the expression above when x = 2 and y = 3

GenaCL600 [577]

Hoi!

To solve this, first plug in the values for x and y.

x = 2, so anywhere you see x, put 2 in its place.

y = 3, so anywhere you see y, put 3 in its place.

$4(2) + \frac{1}{2}(3)$

4 × 2 = 8

$\frac{1}{2}$ × 3 = $1 \frac{1}{2}$

$8 +1 \frac{1}{2}$ = $9 \frac{1}{2}$

$9 \frac{1}{2}$ is your answer.

4 0

3 years ago

Read 2 more answers