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yaroslaw [1]
3 years ago
5

N-6+4=24 solve for n

Mathematics
2 answers:
zubka84 [21]3 years ago
8 0
N= 26
hope this helped !!
anastassius [24]3 years ago
8 0
The answer is n= 26 :))
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A population grows with an annual growth rate of 16.5 % per year. (a) what is the monthly growth rate
Shtirlitz [24]
The monthly growth rate would be 16.5% divided by 12 which is 1.3%
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3 years ago
Which expression is equivalent to 3x + 2.5(4x + 2)?
Alex787 [66]

Answer:

I think its B

Step-by-step explanation:

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6 0
2 years ago
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Are there any integers between 0 and 1? Explain
zvonat [6]

Answer:

No

Step-by-step explanation:

Integers are whole numbers (not decimals or fractions) that are either <u>positive,</u> <u>negative</u>, or <u>zero</u>.

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3 years ago
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A university dean is interested in determining the proportion of students who receive some sort of financial aid. Rather than ex
Olenka [21]

Answer:

a

 The  90% confidence interval that  estimate the true proportion of students who receive financial aid is

     0.533  <  p <  0.64

b

   n = 1789

Step-by-step explanation:

Considering question a

From the question we are told that

      The sample size is  n = 200

      The number of student that receives financial aid is k = 118

Generally the sample proportion is  

      \^ p = \frac{k}{n}

=>   \^ p = \frac{118}{200}

=>   \^ p = 0.59

From the question we are told the confidence level is  90% , hence the level of significance is    

      \alpha = (100 - 90 ) \%

=>   \alpha = 0.10

Generally from the normal distribution table the critical value  of \frac{\alpha }{2}  is  

   Z_{\frac{\alpha }{2} } =  1.645

Generally the margin of error is mathematically represented as  

     E =  Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }

 =>E =  1.645 * \sqrt{\frac{0.59 (1- 0.59)}{200} }

=>  E = 0.057

Generally 90% confidence interval is mathematically represented as  

      \^ p -E <  p <  \^ p +E

  =>  0.533  <  p <  0.64  

Considering question b

From the question we are told that

    The margin of error  is  E = 0.03

From the question we are told the confidence level is  99% , hence the level of significance is    

      \alpha = (100 - 99 ) \%

=>   \alpha = 0.01

Generally from the normal distribution table the critical value  of   is  

   Z_{\frac{\alpha }{2} } = 2.58

Generally the sample size is mathematically represented as      

        [\frac{Z_{\frac{\alpha }{2} }}{E} ]^2 * \^ p (1 - \^ p )

=>      n = [\frac{2.58}{0.03} ]^2 * 0.59 (1 - 0.59 )

=>      n = 1789

8 0
3 years ago
A reindeer can run 96 miles in 3 hours at this rate how far can a reindeer run in 1hour explain
jekas [21]
This is how you do it: you put mile 96 over 3 and if u wanna know how many it will run in 1 hour. You cross multiply so you multiply 96 times1 and you get 96 but now you have to divide it by 3. If you do that you'll get the answer which is 32. There are other ways to do it but I just think it's way easier this way
6 0
3 years ago
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