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VMariaS [17]
3 years ago
14

Simplify this question please im really confused

Mathematics
1 answer:
Gemiola [76]3 years ago
8 0

Answer:

option A

Step-by-step explanation:

\frac{x^a}{x^b} = x^{a-b} , z^0 = 1

So,

\frac{18x^5 y}{6xy^8z^0} = \frac{18}{6} \times x^{5 -1} \times y^{1-8} = 3 x^4 \times y^{-7} = \frac{3x^4}{y^7}

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What mixed number does it show?
Gelneren [198K]
Hi there!

Since there are 4 columns of boxes fully shaded in and one other box with one section shaded in out of 6 sections, the answer would be
4 + 1 of 6, or

4 1/6.

Hope this helps!
5 0
3 years ago
Read 2 more answers
The Quality Control Department employs five technicians during the day shift. Listed below is the number of times each technicia
sveta [45]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the data :

Technician __Shutdown

Taylor, T___4

Rousche, R _ 3

Hurley, H__ 3

Huang, Hu___2

Gupta, ___ 5

The Numbe of samples of 2 possible from the 5 technicians :

We use combination :

nCr = n! ÷ (n-r)!r!

5C2 = 5!(3!)2!

5C2 = (5*4)/2 = 10

POSSIBLE COMBINATIONS :

TR, TH, THu, TG, RH, RHu, RG , HHu, HG, HuG

Sample means :

TR = (4+3)/2 = 3.5

TH = (4+3)/2 = 3.5

THu = (4+2) = 6/2 = 3

TG = (4 + 5) = 9/2 = 4.5

RH = (3+3) = 6/2 = 3

RHu = (3+2) /2 = 2.5

RG = (3 + 5) = 8/2 = 4

HHu = (3+2) = 2.5

HG = (3+5) = 8/2 = 4

HuG = (2+5) / 2 = 3.5

Mean of sample mean (3.5+3.5+3+4.5+3+2.5+4+2.5+4+3.5) / 10 = 3.4

Population mean :

(4 + 3 + 3 + 2 + 5) / 5 = 17 /5 = 3.4

Population Mean and mean of sample means are the same.

This distribution should be approximately normal.

7 0
3 years ago
**WILL MARK BRAINLIEST** PLEASE ANSWER!! please ??
geniusboy [140]

Answer:

Port eagle has the higher median

Step-by-step explanation:

That's all I will give you.

Why?

Because the median is the average which would be the middle range between two points.

7 0
3 years ago
Where are the asymptotes for the following function located? f (x) = StartFraction 14 Over (x minus 5) (x + 1) EndFraction
m_a_m_a [10]

Answer:

2 vertical asymptotes occurring at x = 5 and x = -1

Step-by-step explanation:

given

f(x) = \frac{14}{(x-5)(x+1)}

recall that asymptotic occur at the locations that will make the equation undefined. In this case, the asymptote will occur at x-locations which will cause the denominator to become zero (and hence undefined)

Equating the denominator to zero,

(x-5)(x+1) = 0

(x-5) =0

x = 5 (first asymptote)

or (x+1) = 0

x = -1  (2nd asymptote)

6 0
3 years ago
Given that f(x)=2x+2 evaluate f(1)+f(5)
Svetlanka [38]

Answer:

16

Step-by-step explanation:

To solve this, you need to evaluate the function at f(1), which just means that you have to plug in 1 for any x you see in the equation. For example, here f(1) = 2(1) + 2 which simplifies to 4. Next find f(5). By doing the same process you will find that this is 12. The problem asks for f(1) + f(5) so by putting those values in you will get 4+12=16. Hope this helps! :)

8 0
2 years ago
Read 2 more answers
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