
Note that both the numerator and denominator approach 0 as

, so we can try using L'Hopital's rule.

The denominator is nonzero at

, so the limit is equivalent to
Answer:
Let x = the width of the smaller rectangle.
The length of the smaller rectangle is 2x - 1.
Area is A = lw
So the area of the smaller rectangle is A = (x)(2x - 1) = 2x^2 - x
Step-by-step explanation:
hope it helped
It is most definetly A. the others wouldn't make any sense.
Answer:
c
Step-by-step explanation:
its c