Answer:
Eight and Eight Thousandths
Step-by-step explanation:
The probability distribution for a random variable x is given in the table X: -5,-3,-2,0,2,3 Probability: .17,.13,.33,.16,.11,.1
Ivan
Answer:
0.6 probability that 
Step-by-step explanation:
The probability distribution is given in the table.
Probability that x is between -2 and 2.
Between -2 and 2, inclusive, we have -2, 0 and 2. So
From the table:
. So
0.6 probability that
19 yards divided by 2.5 minutes.
=19/2.5
= 7.6 yards/minute
Complete question :
Birth Month Frequency
January-March 67
April-June 56
July-September 30
October-December 37
Answer:
Yes, There is significant evidence to conclude that hockey players' birthdates are not uniformly distributed throughout the year.
Step-by-step explanation:
Observed value, O
Mean value, E
The test statistic :
χ² = (O - E)² / E
E = Σx / n = (67+56+30+37)/4 = 47.5
χ² = ((67-47.5)^2 /47.5) + ((56-47.5)^2 /47.5) + ((30-47.5)^2/47.5) + ((37-47.5)^2/47.5) = 18.295
Degree of freedom = (Number of categories - 1) = 4 - 1 = 3
Using the Pvalue from Chisquare calculator :
χ² (18.295 ; df = 3) = 0.00038
Since the obtained Pvalue is so small ;
P < α ; We reject H0 and conclude that there is significant evidence to suggest that hockey players' birthdates are not uniformly distributed throughout the year.
Answer:
B. 1
Step-by-step explanation:
I used a calculator
