Step-by-step explanation:
C=2×pi×r
8.61=2pi*×r
8.61÷2pi=13.52 radius
A=pi×r^2
pi×13.52^2=574.25 area
Answer:
400
Step-by-step explanation:
Answer:
![(\frac{13}{5};\frac{6}{5}).](https://tex.z-dn.net/?f=%28%5Cfrac%7B13%7D%7B5%7D%3B%5Cfrac%7B6%7D%7B5%7D%29.)
Step-by-step explanation:
![1)\left \{ {{5x=13} \atop {y=2x-4}} \right. \ 2)\left \{ {{x=\frac{13}{5} } \atop {y=\frac{6}{5} }} \right.](https://tex.z-dn.net/?f=1%29%5Cleft%20%5C%7B%20%7B%7B5x%3D13%7D%20%5Catop%20%7By%3D2x-4%7D%7D%20%5Cright.%20%20%5C%202%29%5Cleft%20%5C%7B%20%7B%7Bx%3D%5Cfrac%7B13%7D%7B5%7D%20%7D%20%5Catop%20%7By%3D%5Cfrac%7B6%7D%7B5%7D%20%7D%7D%20%5Cright.)
short explanation: 1) to add the 1st equation to the 2d; 2) to calculate the value of 'x', then to substitute x=13/5 into the 2d equation and calculate the value of 'y'.
<span>There are 4 long rows and 5 short rows in the theater. x represents the number of chairs in each long row and y represents the number of chairs in each short row.
So, total number of chairs in 4 long rows= 4x
Total number of chairs in 5 short rows = 5y
Total number of chairs in the theater on a normal day = 4x + 5y
When 2 chairs are added to each long row, the number of chairs will change to (x+2).
So, total number of chairs in 4 long rows will be = 4(x+2)
When 3 chairs are added to each short row, the number of chairs will change to (y+3)
So, total number of chairs in 5 short rows will be = 5(y+3)
Thus, total number of chairs in the theater in rush day = 4(x+2) + 5(y+3)
= 4x + 8 + 5y + 15
= 4x + 5y + 23
Thus we can say the number of chairs increase by 23 as compared to a normal day.
</span>
Its 3,167 hope this helped