Let the number of blue marbles be x
number of yellow marbles = x/3
number of green = x- 90
ATQ
x + x/3 + x - 90 = 694
2x + x/3 = 784
(6x + x)/3 = 784
7x/3 = 784
x = 784 x 3/7
x = 112 x 3
x = 336
number of blue marbles = 336
For the answer to the question above, the easiest way to determine is changing every runner's speed into the same unit.
<span>First = 10 m/s </span>
<span>Second = 10 miles/min = 16090.34 / 60 m/s (As 1 mile = 1609.34 meter and 1 min = 60 sec) </span>
<span>Second = 260.82 m/s </span>
<span>Third = 10 cm/hr = 10*(0.01)/60*60 (As 1 cm = 0.01 m and 1 hr = 60*60 sec) </span>
<span>Third = 0.000028 m/s </span>
<span>Fourth = 10 km/sec = 10*1000 m/s (As 1 km = 1000 m and time is already in sec) </span>
<span>Fourth = 10000 m/s </span>
<span>So fastest would be the one who covers the largest distance in 1 sec. It would be the fourth one.</span>
Answer:
39.6 cm
Step-by-step explanation:
Applying
s = 2πrθ/360................ Equation 1
Where s = length of an arc or distance traveled by the minutes hand of the clock during the 42 munites, r = length of the minutes hand of the clock, θ = Angle traveled by the minute hand of the clock for every 42 minutes
From the question,
Given: r = 9 cm, θ = 252°
Constant: π = 22/7 = 3.14
Substitute these values into equation 1
s = (2×3.14×9×252)/360
s = 39.564
s = 39.6 cm
Answer:
(2,8)
x = 2
y = 8
Step-by-step explanation:
<u>The steps are shown in the picture</u>
Answer:
12
Step-by-step explanation:
Simplify \frac{4}{5}G
5
4
G to \frac{4G}{5}
5
4G
.
\frac{4G}{5}+42=2.8G+18
5
4G
+42=2.8G+18
Multiply both sides by 5.
4g + 210 = 14g + 90
Simplify
14G + 90 - 4G to 10G + 90
Subtract 90 from both sides.
210-90=10G210−90=10G
Simplify 210-90210−90 to 120120.
120=10G120=10G
Divide both sides by 1010.
\frac{120}{10}=G
10
120
=G
Simplify \frac{120}{10}
10
120
to 1212.
12=G12=G
Switch sides.
G=12G=12
SORRY ABOUT ALL THIS WORK...
