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2 years ago

Can someone help :)) and pls explain how u got it so i can understand

Mathematics

1 answer:

Leona [35]2 years ago

6 0

Answer:

B) x = 20

Step-by-step explanation:

The formula for finding the missing side of a right triangle is: a^2+b^2=c^2.

C represents the longest side of the right triangle, so if we plug in the given lengths, we can solve: 12^2 + 16^2 = x^2

Solve the exponents: 144 + 256 = x^2

Add: 400 = x^2

Find the square root: 20 = x

You might be interested in

If I can paint a wall in 20 min and my friend can paint a wall in 30 min. How many minutes would it take for us to paint a wall

ra1l [238]

Answer: $12\ \text{min}$

Step-by-step explanation:

Given

It takes 20 min and 30 min for a person and his friend to paint a wall individually i.e.

In 1 min they cover $\frac{1}{20}$ part and $\frac{1}{30}$ part of wall respectively.

If the work together, 1 minute work is

$\Rightarrow \dfrac{1}{20}+\dfrac{1}{30}\\\\\Rightarrow \dfrac{3+2}{60}\\\\\Rightarrow \dfrac{5}{60}$

Time required will be reciprocal of it

$\Rightarrow \dfrac{60}{5}=12\ \text{min}$

3 0

3 years ago

Help it’s for my final most of my grade

Helga [31]

whats the question lol

5 0

2 years ago

If f(x) = 2x^2 + 2, find f(5)

zlopas [31]

Well, following the order of PEMDAS, I got choice B. 52

For instance, when you plug in 5 for x, you get F(5)=2(5)^2+2.

Moreover, following PEMDAS, you're supposed to solve what's inside the parenthesis, but since there is no operation going on inside the parenthesis, then you simple move on to the exponent.

In this case, you square the number 5, which gives you F(5)=2(25)+2

After that, you Multiply (letter M in PEMDAS). This results in F(5)=50+2.

Finally, you add them, which results in F=52.

By the way, I noticed a mistake in your work. When multiplying 2 by 5, the answer is 10, not 20.

Anyway, hope this helped! :-)

8 0

3 years ago

The standard deviation for actuary salaries has a standard deviation of $36,730 . You collect a simple random sample of n=36 sal

Yanka [14]

Using the z-distribution, it is found that the lower limit of the 95% confidence interval is of $99,002.

<h3>What is a z-distribution confidence interval?</h3>

The confidence interval is:

$\overline{x} \pm z\frac{\sigma}{\sqrt{n}}$

In which:

$\overline{x}$ is the sample mean.

z is the critical value.

n is the sample size.

$\sigma$ is the standard deviation for the population.

In this problem, we have a 95% confidence level, hence $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so the critical value is z = 1.96.