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Mashcka [7]
3 years ago
13

A group of 570 students were surveyed about the courses they were taking at their college with the following results:

Mathematics
1 answer:
garri49 [273]3 years ago
7 0

Answer:

The number of students who took English and History, but not Math is 143.

Step-by-step explanation:

Denote the subject choices as follows:

<em>M</em> = a students was taking Math

<em>E</em> = a students was taking English

<em>H</em> = a students was taking History

The data provided is as follows:

N (M) = 257

N (E) = 282

N (H) = 323

n (M ∩ E) = 154

n (M ∩ H) = 171

n (E ∩ H) = 143

n (M ∩ E ∩ H) = 80

Consider the Venn diagram below.

From the provided data and the Venn diagram the value of the set E and H minus M is 143.

Thus, the number of students who took English and History, but not Math is 143.

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bulgar [2K]

Answer:

y = -4

Step-by-step explanation:

First, let's find the slope. Since the line is horizontal, it's slope has to be 0 (this is because slope = rise/run, there is no "rise" in a horizontal line therefore the slope is 0)

Now, we need to find the y-intercept. This is where the line intercepts the y-axis. Looking at the graph, the line intercepts the axis at (0,-4), therefore the y-intercept is -4.

The equation would be:

y=0x-4

y=-4

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2 years ago
joseph has a new rectangular aquarium. the aquarium has a length of four feet, width of two feet and height of two feet. What is
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12 inches go into one foot, so we can calculate the volume of the tank in inches to make the calculations that follow easier. Therefore, to calculate the volume of the tank, we use length x breadth x height = 4 x 2 x 2 = 16 square feet x 12 for square inches = 192 square inches. 
Every 12 square inches Joseph can fit a one inch fish. The fish that he has are 3 inches long, therefore he can only fit one fish every 36 square inches. 
That means that if we take the total volume of the tank and divide it by the space that a 3 inch fish will take up, we are left with 192/36 = 5.3 fish.
You cannot have a third of a fish, so we round off to the nearest whole number, and we determine that Joseph can put 5 fish in his new aquarium.
3 0
3 years ago
The expression 3[x-9) is equivalent to<br> 03(x)+9.<br> 03(x)+3(9)<br> O 3(%) - 9.<br> 03(x) – 3(9)
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Answer:

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Step-by-step explanation:

5 0
3 years ago
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Witch of the following expression is equivalent to the logarithmic expression below. log(3)5/x^2
BabaBlast [244]
Assuing you mean
log_{3}(\frac{5}{x^2})
remember that log(\frac{a}{b})=log(a)-log(b)
also, log(x^m)=(m)log(x)

so
log_{3}(\frac{5}{x^2})=
log_{3}(5)-log_{3}(x^2)=
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4 0
3 years ago
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Use the model below to estimate the average annual growth rate of a certain country's population for 1950, 1988, and 2010, where
Morgarella [4.7K]

Answer:

The average annual growth rate of a certain country's population for 1950, 1988, and 2010 are 2.398, 0.9985 and 0.2236 respectively.

Step-by-step explanation:

The given equation is

Y=-0.0000084x^3+0.00211x^2-0.205x+8.423

Where Y is the annual growth rate of  a certain country's population and x is the number of years after 1900.

Difference between 1950 and 1900 is 50.

Put x=50 in the given equation.

Y=-0.0000084(50)^3+0.00211(50)^2-0.205(50)+8.423

Y=2.398

Therefore the estimated average annual growth rate of the country's population for 1950 is 2.398.

Difference between 1988 and 1900 is 88.

Put x=88 in the given equation.

Y=-0.0000084(88)^3+0.00211(88)^2-0.205(88)+8.423

Y=0.9984752\approx 0.9985

Therefore the estimated average annual growth rate of the country's population for 1988 is 0.9985.

Difference between 2010 and 1900 is 110.

Put x=110 in the given equation.

Y=-0.0000084(110)^3+0.00211(110)^2-0.205(110)+8.423

Y=0.2236

Therefore the estimated average annual growth rate of the country's population for 2010 is 0.2236.

8 0
3 years ago
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