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2 years ago

PLEASE HELP!!! What is mDBC?

Mathematics

2 answers:

defon2 years ago

7 0

Answer:

i dont get the question sorry

Step-by-step explanation:

Studentka2010 [4]2 years ago

3 0

Combine like terms. Add up the numbers with the x.(3x+x) will give you 4x. Now you will subtract 4 from 22 and you will get 18 now you will divide 4 from 18 and you will get a decimal but round it up and it should be 4? If not then instead of adding x to 3x subtract x from 3 and you get 2x now the 18 from earlier you divide 2 from 18 and you will get 9. I hope this helps !

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b) 0.9609

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 76503

Standard Deviation, σ = 8850

We are given that the distribution of annual salaries is a bell shaped distribution that is a normal distribution.

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$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

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P(x > 100000)

$P( x > 100000) = P( z > \displaystyle\frac{100000 - 76503}{8850}) = P(z > 2.655)$

$= 1 - P(z \leq 2.655)$

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b) P(sample mean annual salary falls between 70,000 and 80,000 dollars)

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Standard error due to sampling =

$\dfrac{\sigma}{\sqrt{n}} = \dfrac{8850}{\sqrt{20}} = 1978.92$

$P(70000 \leq x \leq 80000) = P(\displaystyle\frac{70000 - 76503}{1978.92} \leq z \leq \displaystyle\frac{80000-76503}{1978.92})\\\\ = P(-3.286 \leq z \leq 1.767)\\\\= P(z \leq 1.767) - P(z < -3.286)\\=0.9614 - 0.0005= 0.9609 = 96.09\%$

$P(70000 \leq x \leq 80000) = 96.09\%$

7 0

2 years ago

PLEASE HELP!!! What is mDBC?​

PLEASE HELP!!! What is mDBC?