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stiks02 [169]
3 years ago
10

I see 2 people sitting on the bench at the playground. One was Deaf and one was blind.

Mathematics
1 answer:
True [87]3 years ago
5 0

Answer:

the blind one

Step-by-step explanation:

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Alchen [17]

180 = 93 +3x +18

180 =111 +3x

3x = 180-111

3x = 69

x = 69/3

x = 23

8 0
3 years ago
Need help fast with this question fourty points and branliest!!
Colt1911 [192]

You can use SAS, or Side Angle Side. Because BC equals EC and AC equals DC, you can get two sides. Also, angle BCA and DCE have the same angle measurement, so you can conclude, using SAS, that BA equals to ED. Also, you can also prove that these two triangles are congruent and that all of the angles are the same as well because all of the side lengths are equal.


8 0
3 years ago
Read 2 more answers
The equation which correctly represents this situation is
uranmaximum [27]

Answer:

C) x2 + x = 306

Step-by-step explanation:

x2 + x = 306

x2 + x - 306  = 0

x2  + 18x - 17x + 18 * (-17) = 0

x ( x + 18) - 17 (x +18) =0

(x + 18) (x - 17 ) = 0

x = -18 or 17

5 0
3 years ago
Please help me I love u
r-ruslan [8.4K]
45 is the answer have a really good day
4 0
3 years ago
Solve the following quadratic equation by completing the square ✓3x^2 + 10x + 7✓3 = 0​
solmaris [256]

\sqrt{3}x^2+10x+7\sqrt{3}=0\\\\\sqrt3(x^2+\dfrac{10x}{\sqrt{3}}+7)=0\\\\x^2+\dfrac{10x}{\sqrt{3}}+7=0\\\\x^2+\dfrac{10x}{\sqrt{3}}+\dfrac{25}{3}-\dfrac{25}{3} +7=0\\\\(x+\dfrac{5}{\sqrt{3}})^2 = \dfrac{4}{3}\\\\|x+\dfrac{5}{\sqrt{3}}| = \dfrac{2}{\sqrt{3}}\\\\x_1 =   \dfrac{2}{\sqrt{3}}-\dfrac{5}{\sqrt{3}} = -\dfrac{3}{\sqrt{3}} = -\sqrt{3}\\\\x_2 =    -\dfrac{2}{\sqrt{3}}-\dfrac{5}{\sqrt{3}} = \dfrac{-7}{\sqrt{3}} = -\dfrac{-7\sqrt{3}}{3}

5 0
3 years ago
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