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GuDViN [60]
2 years ago
7

Somebody help me with this please

Mathematics
1 answer:
ziro4ka [17]2 years ago
3 0
The correct answer is c
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Aleksandr-060686 [28]
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1/2
Why?
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2 years ago
Add the following<br><br> - 62 + (- 65)=
Ainat [17]

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-127

Step-by-step explanation:

7 0
2 years ago
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A= 1/2 h (m+n)<br> solve for n
melisa1 [442]

Answer:

2hms+2hns

Step-by-step explanation:

3 0
2 years ago
Kareem wrote the values shown below.
sweet [91]

Answer:  Option 'B' is correct.

Step-by-step explanation:

Since we have given that

[3.2] [2.7] [2.9] [4.8]

Since they are all of greatest integer functions i.e.

f(x) = [x]

It is known as greatest integer function whose value is always less than or equal to 'x'.

So, [3.2]=3

[2.7]=2

[2.9]=2

[4.8]=4

so, we can see that [2.7] and [2.9] is a equivalent pair.

Hence, Option 'B' is correct.

4 0
3 years ago
Read 2 more answers
(5x^3-8x^2+9x+12)/(x-3)<br><br> please answer with sentences on how to do it step by step. thanks!
Anastaziya [24]

Answer:

5x^2+7x+30+\frac{102}{x-3}

Step-by-step explanation:

\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}5x^3-8x^2+9x+12\\\mathrm{and\:the\:divisor\:}x-3\mathrm{\::\:}\frac{5x^3}{x}=5x^2\\\mathrm{Quotient}=5x^2\\\mathrm{Multiply\:}x-3\mathrm{\:by\:}5x^2:\:5x^3-15x^2\\\mathrm{Subtract\:}5x^3-15x^2\mathrm{\:from\:}5x^3-8x^2+9x+12\mathrm{\:to\:get\:new\:remainder}\\\mathrm{Remainder}=7x^2+9x+12\\\mathrm{Therefore}\\=5x^2+\frac{7x^2+9x+12}{x-3}

\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}7x^2+9x+12\\\mathrm{and\:the\:divisor\:}x-3\mathrm{\::\:}\frac{7x^2}{x}=7x\\\mathrm{Quotient}=7x\\\mathrm{Multiply\:}x-3\mathrm{\:by\:}7x:\:7x^2-21x\\\mathrm{Subtract\:}7x^2-21x\mathrm{\:from\:}7x^2+9x+12\mathrm{\:to\:get\:new\:remainder}\\\mathrm{Remainder}=30x+12\\\mathrm{Therefore}\\=5x^2+7x+\frac{30x+12}{x-3}\\

\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}30x+12\\\mathrm{and\:the\:divisor\:}x-3\mathrm{\::\:}\frac{30x}{x}=30\\\mathrm{Quotient}=30\\\mathrm{Multiply\:}x-3\mathrm{\:by\:}30:\:30x-90\\\mathrm{Subtract\:}30x-90\mathrm{\:from\:}30x+12\mathrm{\:to\:get\:new\:remainder}\\\mathrm{Remainder}=102\\\mathrm{Therefore}\\=5x^2+7x+30+\frac{102}{x-3}

6 0
2 years ago
Read 2 more answers
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