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3 years ago

PLEASE HELPP IM TIMED I'LL DIE I'LL GIVE BRAINLIEST AND 50 POINTSSS

Mathematics

1 answer:

spayn [35]3 years ago

4 0

9514 1404 393

Answer:

3x -4y = -9

Step-by-step explanation:

Multiply by 4 to clear the fraction.

4(y -6) = 3(x -5)

Subtract the left-side term to get variables on the same side, with a positive x-coefficient.

0 = 3(x -5) -4(y -6)

Eliminate parentheses and collect terms.

0 = 3x -15 -4y +24

0 = 3x -4y +9

Subtract 9 and swap sides to get standard form.

3x -4y = -9

_____

Standard form is ...

ax +by = c

where a ≥ 0, and a, b, c are mutually prime integers. If a=0, then b > 0.

The attached graph shows the equations give the same line. The original line is shown dotted so that you can see they overlap.

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You have quarters and dimes that total $2.80. your friend says it is possible that the number of quarters is 8 more than the num

ss7ja [257]

To answer this question, you need to know that a quarter is worth $0.25 and dimes worth $0.10. In this case, the total number of money that made from quarters and dimes is $2.80
With Q=quarter and D=dime, then the equation should be:
2.80= 0.25 Q + 0.10 D

The condition that needs to be fulfilled in this case is that the quarter should be 8 more than dimes. Then you need to find out the highest possible number of the quarter and lowest possible number of the dimes.
If you divide 2.8 with 0.25 you will found it will be 11.2 but 11 quarter will result with 0.05 value which you cannot remove, so the highest possible of the quarter should be 10.
If the highest possible of the quarter is 10, then the lowest possible of dimes should be:
2.8= 0.25(10) + 0.10D
0.10D= 0.3
D=3

Since 10-3 is 7, then it is not possible for the quarter to be 8 more than the dimes.

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3 years ago

Find the greatest common factor 15x^2 y^3, and -20x^3 yz.

alexgriva [62]

15x^2y^3=3*5*x*x*y*y*y
-20x^3yz=-1*2*2*5*x*x*x*y*z
comon numbers are
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4 years ago

Read 2 more answers

A large city in the ancient world was square-shaped. measured in miles, its area numerically exceeded its perimeter by about 132

melisa1 [442]

Area = perimeter + 132.

Let each side of the city be x miles long, then:-

x^2 = 4x + 132
x^2 - 4x - 132 = 0

x = [-(-4) +/- sqrt((-4)^2 - 4 * 1 *-132)] / 2

x = 13.66, -9.66 We ignore the negative

So the city has dimension of 13.66 * 13.66

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3 years ago

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Answer: 51?

Warning!:

I might be wrong because I haven't done this in a long time, so make sure to double-check.

Other than that, I hope this helps!

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ZanzabumX [31]

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