Answer:
sin(a)=20/29
cos(a)=21/29
<span>Exactly 33/532, or about 6.2%
This is a conditional probability, So what we're looking for is the probability of 2 gumballs being selected both being red. So let's pick the first gumball.
There is a total of 50+150+100+100 = 400 gumballs in the machine. Of them, 100 of the gumballs are red. So there's a 100/400 = 1/4 probability of the 1st gumball selected being red.
Now there's only 399 gumballs in the machine and the probability of selecting another red one is 99/399 = 33/133.
So the combined probability of both of the 1st 2 gumballs being red is
1/4 * 33/133 = 33/532, or about 0.062030075 = 6.2%</span>
Number of containers for 2 litres of water = 1
So, number of containers for 1 litre of water = ½
So, number of containers for 30 litres of water
= ½ × 30
= 30/2
= 15
So, 15 of these containers would be needed to fill a 30-liter drum.
Answer:
7.855
Step-by-step explanation:
A=pi*r^2=3.142*5^2=3.142*25=7.855
