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kykrilka [37]
2 years ago
9

PLEASE HELP MEEEEEEEE!! I ONLY NEED NUMBER 2!! I WILL VOTE BRIANLYIST​

Mathematics
1 answer:
N76 [4]2 years ago
6 0

Answer:

(3,3)

Step-by-step explanation:

2)  solve for 'x':    2/3x + 1 = 4/3x - 1

1 = 2/3x - 1

2x = 6

x = 3

now solve for 'y':

y = 2/3(3) + 1

y = 2 + 1

y = 3

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Homework help, please
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Start the line at 3 on the y-axis (vertical). then go down two boxes and to the right three & make a mark at that point. keep going down two and over three until the end of the graph. then just connect the marks.
4 0
3 years ago
Work out m and c for the line: 3 y + 6 x = − 3
Usimov [2.4K]

Answer:

<u>m</u><u> </u><u>is</u><u> </u><u>-</u><u>2</u><u> </u><u>and</u><u> </u><u>c</u><u> </u><u>is</u><u> </u><u>-</u><u>1</u>

Step-by-step explanation:

• Let's first phrase out the general equation of a line

{ \rm{y = mx + c}}

  • m is the slope
  • c is the y-intercept

[ remember that a general line equation must be in slope - intercept form as shown above ]

• from our question, we are given the equation;

{ \rm{3y + 6x =  - 3}}

• let's make y the subject in order to make the equation in slope - intercept format.

→ <em>r</em><em>e</em><em>m</em><em>e</em><em>m</em><em>b</em><em>e</em><em>r</em><em> </em><em>t</em><em>o</em><em> </em><em>a</em><em>p</em><em>p</em><em>l</em><em>y</em><em> </em><em>"</em><em>s</em><em>u</em><em>b</em><em>j</em><em>e</em><em>c</em><em>t</em><em> </em><em>m</em><em>a</em><em>k</em><em>i</em><em>n</em><em>g</em><em> </em><em>k</em><em>n</em><em>o</em><em>w</em><em>l</em><em>e</em><em>d</em><em>g</em><em>e</em><em>"</em>

{ \rm{3y =  - 3 - 6x}} \\  \\ { \rm{3y =  - 6x - 3}} \\  \\ { \rm{ \frac{3y}{3}  =  \frac{ - 6x}{3}  -  \frac{3}{3} }} \\  \\  { \boxed{ \rm{y =  - 2x - 1}}}

• The above boxed equation is now a general equation. Let's extract out slope, m and y-intercept, c

{ \rm{m \:  \dashrightarrow \:  - 2}} \\  \\ { \rm{c \:  \dashrightarrow \:  - 1}}

8 0
3 years ago
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Anit [1.1K]

Answer:

? Is 41 degrees

Step-by-step explanation:

SOH CAH TOA

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Hypotenuse and adjacent - Cos

(Cos inverse to find the angle)

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? = 41.40962211

Hope this helps!

5 0
2 years ago
Read 2 more answers
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soldi70 [24.7K]

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No

Step-by-step explanation:

gftgffgtftyty

8 0
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Triangle A'B'C' is a reflection of triangle ABC across line BC. Prove that ray BC is the angle bisector of angle ABA'.​
hammer [34]

Answer is below in the picture:-

(From the problem, we know (triangle)ABC (round of equal of) (triangle)A'B'C'. So, <A'B'C' = <ABC {the properties of congruent triangles}. So, ray BC is the angle, bisector of angle ABA')

I hope it helps.

7 0
2 years ago
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