What is the value of m in the equation? 16 + 9 = m - 2 A.25 B.23 C.27 D.29

In-s [12.5K]

This is what I get not sure if the problem on numerator is together if it is then . X^2+(a^2+1) x^2+a^2+1. -----------------= ----------------- AX+1. Ax+1 Answer: a^2+x^2+1 ---------------- AX+1 If I wrote the actual problem wrong let me know. This is what I understood.

5 0

3 years ago

What is the eccentricity of a completely flat ellipse

fredd [130]

It is how close it's form is to that of a circle, there is a formula for it that can be easily searched

6 0

3 years ago

Ratio of the number of students in art class to the number of students in gym class was 2:7, however art class is small, and gym

xenn [34]

Semester 1:

let the number of students in the art class be 2a, and the number of the students in the gym class be 7a. (check: the ratio is 2a:7a = 2:7)

so the total number of students is 9a.

semester 2:

the 9a students are go to the art class and gym class at a a ratio of 5: 4,

so 5a students go to the art class, and 4a students go to the gym class.

75 students are in art class in second semester means that 5a=75,

so a=75/5=15.

In the 1st semester the number of students was:

art class: 2a=2*15=30

gym class: 7a=7*15=105

7 0

3 years ago

The radius of a cone is decreasing at a constant rate of 7 inches per second, and the volume is decreasing at a rate of 948 cubi

inessss [21]

Answer:

The height of cone is decreasing at a rate of 0.085131 inch per second.

Step-by-step explanation:

We are given the following information in the question:

The radius of a cone is decreasing at a constant rate.

$\displaystyle\frac{dr}{dt} = -7\text{ inch per second}$

The volume is decreasing at a constant rate.

$\displaystyle\frac{dV}{dt} = -948\text{ cubic inch per second}$

Instant radius = 99 inch

Instant Volume = 525 cubic inches

We have to find the rate of change of height with respect to time.

Volume of cone =

$V = \displaystyle\frac{1}{3}\pi r^2 h$

Instant volume =

$525 = \displaystyle\frac{1}{3}\pi r^2h = \frac{1}{3}\pi (99)^2h\\\\\text{Instant heigth} = h = \frac{525\times 3}{\pi(99)^2}$

Differentiating with respect to t,

$\displaystyle\frac{dV}{dt} = \frac{1}{3}\pi \bigg(2r\frac{dr}{dt}h + r^2\frac{dh}{dt}\bigg)$

Putting all the values, we get,

$\displaystyle\frac{dV}{dt} = \frac{1}{3}\pi \bigg(2r\frac{dr}{dt}h + r^2\frac{dh}{dt}\bigg)\\\\-948 = \frac{1}{3}\pi\bigg(2(99)(-7)(\frac{525\times 3}{\pi(99)^2}) + (99)(99)\frac{dh}{dt}\bigg)\\\\\frac{-948\times 3}{\pi} + \frac{2\times 7\times 525\times 3}{99\times \pi} = (99)^2\frac{dh}{dt}\\\\\frac{1}{(99)^2}\bigg(\frac{-948\times 3}{\pi} + \frac{2\times 7\times 525\times 3}{99\times \pi}\bigg) = \frac{dh}{dt}\\\\\frac{dh}{dt} = -0.085131$

Thus, the height of cone is decreasing at a rate of 0.085131 inch per second.

3 0

3 years ago

Olivia went to buy shoes at the mall. The shoes cost $55. If tax was 8%, how much did Olivia pay in all? i don't understand it

Alik [6]

Answer:

$59.40

Step-by-step explanation:

8% is equal to 0.08

since you are adding the tax to the original cost you will multiply 55 by 1.08 to get the cost of the shoes plus the tax.

5 0

3 years ago

Read 2 more answers