So if it is 3x^2+4x=2 then
set one side to zero
subtract 2 from both sides
3x^2+4x-2=0
this is not factorable by normal means so use quadratic formula which is if you have the equation in ax^2+bx+c=0 form you can solve for x if you put it into this equation quadratic formula
so if you were to input it into this equation you would get
a=3
b=4
c=-2
the solution is
the answer is C
Answer:
then get un stuck
Step-by-step explanation:
I think he is not correct because there is negative number so it can't be greater than one
Answer:
7s²7p⁴
Step-by-step explanation:
Livermorium is located in the seventh period and sixteenth column of the periodic table. The noble gas configuration for livermorium is [Rn]7s²5f¹⁴6d¹⁰7p⁴. The valence electrons are the ones in the orbitals with the highest quantum number (coefficient). Remember, there can be up to 8 valence electrons at one time. Therefore, the valence electron configuration is 7s²7p⁴.
Answer:
The minimum value of f(x) is -21 and it occurs at x = 1
Step-by-step explanation:
f(x) =3x^2-6x-18
Factor out the greatest common factor out of the first two terms
f(x) =3(x^2-2x)-18
Complete the square
-2x/2 =-1 (-1)^2 = 1
Add 1 (But remember the 3 out front so we are really adding 3 so we need to subtract 3 to remain balanced)
f(x) = 3(x^2 -2x+1) -3 -18
f(x) = 3(x-1)^2 -21
This is vertex form
f(x) = a(x-h)^2 +k where (h,k) is the vertex and a is a constant
The vertex is (1,-21)
Since a > 0 this opens upward and the vertex is a minimum
The minimum value of f(x) is -21 and it occurs at x = 1
