Answer:
The proof is below
Step-by-step explanation:
Given a parallelogram ABCD. Diagonals AC and BD intersect at E. We have to prove that AE is congruent to CE and BE is congruent to DE i.e diagonals of a parallelogram bisect each other.
In ΔACD and ΔBEC
AD=BC (∵Opposite sides of a parallelogram are equal)
∠DAC=∠BCE (∵Alternate angles)
∠ADC=∠CBE (∵Alternate angles)
By ASA rule, ΔACD≅ΔBEC
By CPCT(Corresponding Parts of Congruent triangles)
AE=EC and DE=EB
Hence, AE is conruent to CE and BE is congruent to DE
I prefer to use fractions for some irrational numbers.
For example, 1/3 is equal to an infinite 0.3333333333333333...
They all 3 have no solution!
Answer:
x= -2
Step-by-step explanation:
The first thing I did was isolate the x's on one side. I subtracted 38x from both sides. This gives me:
-9x=18.
Now i divide both sides by -9. Giving me x=-2
Answer:
2x+5y+1=0
y=
Step-by-step explanation:
