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kherson [118]
3 years ago
15

Ralph is arranging a wedding reception. He can spend no more than $8000. It costs $6000 to rent the hall and $25 to feed each gu

est. Ralph needs to know how many guests, at most, can attend the reception. Write an inequality to represent this situation.
Mathematics
1 answer:
BlackZzzverrR [31]3 years ago
8 0

Answer:  

80 ≥ x

Step-by-step explanation:

So we know that he cannot spend more than $8000.

So we subtract 6000 from 8000

8000 - 6000 =2000

So that means<em> $2000 to feed each guest</em>

<em />

<em>We then divide the amount of money we have left by how much it costs to feed each guest.</em>

<em>2000÷25=80</em>

<em>So at most 80 guests will be able to attend. I'll use x to represent the amount of people that will attend the reception.</em>

<em>So </em><em>80 ≥ x</em>

If I am wrong please comment so that I can fix it.

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5\frac{6}{7}+8\frac{1}{14} =13+\frac{13}{14}=13\frac{13}{14}

<h3><em>Hope I helped you!</em></h3><h3><em>Success!</em></h3>
7 0
3 years ago
PLZ HELP
nasty-shy [4]

Answer:

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3 years ago
Each year for 4 years, a farmer increased the number of trees in a certain orchard by of the number of trees in the orchard the
Neko [114]

Answer:

The number of trees at the begging of the 4-year period was 2560.

Step-by-step explanation:

Let’s say that x is number of trees at the begging of the first year, we know that for four years the number of trees were incised by 1/4 of the number of trees of the preceding year, so at the end of the first year the number of trees wasx+\frac{1}{4} x=\frac{5}{4} x, and for the next three years we have that

                             Start                                          End

Second year     \frac{5}{4}x --------------   \frac{5}{4}x+\frac{1}{4}(\frac{5}{4}x) =\frac{5}{4}x+ \frac{5}{16}x=\frac{25}{16}x=(\frac{5}{4} )^{2}x

Third year    (\frac{5}{4} )^{2}x-------------(\frac{5}{4})^{2}x+\frac{1}{4}((\frac{5}{4})^{2}x) =(\frac{5}{4})^{2}x+\frac{5^{2} }{4^{3} } x=(\frac{5}{4})^{3}x

Fourth year (\frac{5}{4})^{3}x--------------(\frac{5}{4})^{3}x+\frac{1}{4}((\frac{5}{4})^{3}x) =(\frac{5}{4})^{3}x+\frac{5^{3} }{4^{4} } x=(\frac{5}{4})^{4}x.

So  the formula to calculate the number of trees in the fourth year  is  

(\frac{5}{4} )^{4} x, we know that all of the trees thrived and there were 6250 at the end of 4 year period, then  

6250=(\frac{5}{4} )^{4}x⇒x=\frac{6250*4^{4} }{5^{4} }= \frac{10*5^{4}*4^{4} }{5^{4} }=2560.

Therefore the number of trees at the begging of the 4-year period was 2560.  

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