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sp2606 [1]
3 years ago
10

can anyone help me out here? I will pay you 20 points

Mathematics
1 answer:
Cerrena [4.2K]3 years ago
8 0

Answer:

The ordered pair that makes an equation true is called a solution

a)solution

b) not a solution

c) solution

d) solution

e)not a solution

f) not a solution

g) solution

h) not a solution

Step-by-step explanation:

The first number in an ordered pair is x, the second one is y

Plug in the numbers to x and y respectively

I'll give two examples so you know how to solve it

a) y=3x+1

-5=3(-2)+1

make sure you use pemdas (multiply first)

-5=-6+1

add

-5=-5

this is true (meaning it is a solution)

b) 6=3(-3) +1

6=-9+1

6 = -8

this is NOT true (not a solution)

If you have any questions feel free to ask

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3 years ago
You throw a ball up and its height h can be tracked using the equation h=2x^2-12x+20.
postnew [5]

<em><u>This problem seems to be wrong because no minimum point was found and no point of landing exists</u></em>

Answer:

1) There is no maximum height

2) The ball will never land

Step-by-step explanation:

<u>Derivatives</u>

Sometimes we need to find the maximum or minimum value of a function in a given interval. The derivative is a very handy tool for this task. We only have to compute the first derivative f' and have it equal to 0. That will give us the critical points.

Then, compute the second derivative f'' and evaluate the critical points in there. The criteria establish that

If f''(a) is positive, then x=a is a minimum

If f''(a) is negative, then x=a is a maximum

1)

The function provided in the question is

h(x)=2x^2-12x+20

Let's find the first derivative

h'(x)=4x-12

solving h'=0:

4x-12=0

x=3

Computing h''

h''(x)=4

It means that no matter the value of x, the second derivative is always positive, so x=3 is a minimum. The function doesn't have a local maximum or the ball will never reach a maximum height

2)

To find when will the ball land, we set h=0

2x^2-12x+20=0

Simplifying by 2

x^2-6x+10=0

Completing squares

x^2-6x+9+10-9=0

Factoring and rearranging

(x-3)^2=-1

There is no real value of x to solve the above equation, so the ball will never land.

This problem seems to be wrong because no minimum point was found and no point of landing exists

3 0
3 years ago
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Each side of the triangle of the dilated triangle will be 2.5 times the length of the original sides.

The area will increase to 2.5^2 = 6.25 times.

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Answer:

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