Answer:
a) the average CPI for machine M1 = 1.6
the average CPI for machine M2 = 2.5
b) M1 implementation is faster.
c) the clock cycles required for both processors.52.6*10^6.
Explanation:
(a)
The average CPI for M1 = 0.6 x 1 + 0.3 x 2 + 0.1 x 4
= 1.6
The average CPI for M2 = 0.6 x 2 + 0.3 x 3 + 0.1 x 4
= 2.5
(b)
The average MIPS rate is calculated as: Clock Rate/ averageCPI x 10^6
Given 80MHz = 80 * 10^6
The average MIPS ratings for M1 = 80 x 10^6 / 1.6 x 10^6
= 50
Given 100MHz = 100 * 10^6
The average MIPS ratings for M2 = 100 x 10^6 / 2.5 x 10^6
= 40
c)
Machine M2 has a smaller MIPS rating
Changing instruction set A from 2 to 1
The CPI will be increased to 1.9 (1*.6+3*.3+4*.1)
and hence MIPS Rating will now be (100/1.9)*10^6 = 52.6*10^6.
Answer:
The program to this question can be given as:
Program:
#include <stdio.h> //include header file.
int main() //defining main method
{
char i,j; //defining variable
for (i='a'; i<='e'; i++) //outer loop for column
{
for (j='a'; j<='e'; j++) //inner loop for row
{
printf("%c%c\n",i,j); //print value
}
}
return 0;
}
Output:
image.
Explanation:
- In the above C language program, firstly a header file is included. Then the main method is defined in this, a method contains a char variable that is "i and j". This variable is used in for loop, that is used to print the pattern.
- To print the following patter two for loop is used the outer loop is used for print columns and the inner loop prints row.
- In C language to print character, we use "%c" inside a loop print function is used, that prints characters.
Answer:
the visibility persists as long as both A and B exist.
Explanation:
Global visibility basically means that the visibility persists as long as both A and B exist. In programming global visibility signifies that the variable/data in question is visible from any context of the code. Meaning that it can be accessed and manipulated from any part of the code, even from within a function or another document. This makes it very easy to use and structure accordingly.
Answer:B kept at a secure location at the facility
Explanation:
Enge extrapolated this analysis across the 2.2 billion<span> users on Google and concluded that while the “active profiles” on Google+ amount to </span>111 million<span> users, only 6.7 million users have 50 or more posts ever, and only 3.5 million have 50 or more posts in the last 30 days</span>
