Hello :
f'(7) = the slope of the tangent line : let A(7,4) B(0,3)<span>
<span>the slope is : (YB - YA)/(XB -XA)= (3-4)/(0-7) = -1/-7 = 1/7=f'(7)
the equation of the tangent line is :
y-3 = 1/7 (x-0)
y = (1/7)x+3
the line tangent and the graph of : f </span></span><span>passes through the point A(7, 4)
x= 7 y=4 so : f(7) =4</span>
I have uploaded a link! The answer is in the link below:
http://www.vegetablefacts.net/vegetable-history/history-of-butthole/
453 + 557 = 1010
P = 0
B = 5 <==
C = 3 <==
Q = 1
Answer:
t < 1/2
Step-by-step explanation:
Isolate the <u>v</u><u>a</u><u>r</u><u>i</u><u>a</u><u>b</u><u>l</u><u>e</u> by dividing each side by <u>f</u><u>a</u><u>c</u><u>t</u><u>o</u><u>r</u><u>s</u> that don't contain the <u>v</u><u>a</u><u>r</u><u>i</u><u>a</u><u>b</u><u>l</u><u>e</u>.
Inequality Form: t < 1/2
Interval Notation: ( -infinity, 1/2)
In this item, I assume that the variable "e" here stands for the Euler number which is equal to 2.718. Raising this number to the exponent -2.8 will give us an answer of,
y = e^-2.8 = (2.718)^-2.8 = 0.0608
Therefore, the value of y is approximately 0.1.
