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Lisa [10]
3 years ago
7

in 2009, a gullop poll found that 47% of Americans favored protection of the environment at the risk of limiting energy supplies

, while 46% favored the development of u.s energy supplies even if that risked harming the environment. Another 3% felt that energy and the environment were equally important. a) based on the poll, whats the probability a person had "no opinion"? b) Whats the probability of that a respondent rated protecting the environment as equally important or more important than developing energy sources
Mathematics
1 answer:
Vikki [24]3 years ago
5 0

Answer:

your

Step-by-step explanation:

welcome

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u can look this up here on brainly for an answer source if you want but do the one that has the greatest points... its on google
Alla [95]

Answer:

First one is 41

Second one is 87

Step-by-step explanation:

Make the shaded part as a trapezoid which is (3+6)*10/2 you just have to get rid of 2*2. So you get 41 as the answer.

The unshaded part will be 16*8 then subtracts the shaded part which is 41.  Then you get the answer 87.

6 0
3 years ago
Help with this please
Harlamova29_29 [7]
If C is the MIDPOINT of BD, and BD equals 12, then what does CD equal?
AD = AC+CD, so you only need to find length of CD and add length of AC (which you already have) to it.
Hope this helps
3 0
3 years ago
Suppose the standard deviation of a normal population is known to be 3, and H0 asserts that the mean is equal to 12. A random sa
blagie [28]

Answer:

z=\frac{12.95-12}{\frac{3}{\sqrt{36}}}=1.9  

p_v =P(z>1.9)=0.0287  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 12 at 5% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=12.95 represent the sample mean

\sigma=3 represent the population standard deviation for the sample  

n=36 sample size  

\mu_o =12 represent the value that we want to test  

\alpha=0.05 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is equal to 12, the system of hypothesis would be:  

Null hypothesis:\mu \leq 12  

Alternative hypothesis:\mu > 12  

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

z=\frac{12.95-12}{\frac{3}{\sqrt{36}}}=1.9  

P-value  

Since is a right tailed test the p value would be:  

p_v =P(z>1.9)=0.0287  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 12 at 5% of signficance.  

4 0
3 years ago
Read 2 more answers
Please help! i need this asap
Westkost [7]
Philip equation
ordered data: 3o(oranges), 3g(green), 6y, 8r, 13b(black, 15b(blue
mean: 8 mode: 3 range: 12
8 0
2 years ago
--(4+h) = 3h<br> What is H
butalik [34]
H= -1

Distribute:

-(4+h)= -4 - h

-4 - h= 3h

-4 +h = 3h + h

-4= 4h

-1 = h
7 0
3 years ago
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