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Naya [18.7K]
3 years ago
12

Hello, I need help answering and explaining the question in the attached image. It includes the figures plus the question and th

e multiple choice answers. Thank you!

Physics
1 answer:
Flauer [41]3 years ago
8 0

Answer:

d.

Explanation:

Since the dart's initial speed v at angle has both vertical and horizontal components v₀sinθ and v₀cosθ respectively, the vertical component of the speed continues to decrease until it hits the target. It's displacement ,s is gotten from

s = y - y₀ = (v₀sinθ)t - 1/2gt² where y₀ = 0 m

y - 0 = (v₀sinθ)t - 1/2gt²

y = (v₀sinθ)t - 1/2gt²

which is the parabolic equation for the displacement of the dart.

Note that the horizontal component of the dart's velocity does not change during its motion.

Since the target falls vertically, with initial velocity u = 0 (since it was stationary before the string cut), it's displacement ,s' is gotten from

s' = y - y₀' = ut - 1/2gt² where y₀' = initial height of target above the ground

= (0 m/s)t - 1/2gt²

= 0 - 1/2gt²

y - y₀' = - 1/2gt²

y = y₀' - 1/2gt²

which is the parabolic equation for the displacement of the target.

The equation for both the displacement of the dart and the target can only be gotten if we considered vertical motion. So, the displacement component of both the dart and target are both vertical.

So, the answer is d.

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Por un solenoide de 6500 espiras y 25 cm de longitud circula una corriente de 0,6 amperios. ¿Cuál es el valor del campo magnétic
9966 [12]

Answer:

Magnetic field, B = 0.0196 T

Explanation:

A current of 0.6 amps flows through a solenoid 6500 turns and 25 cm long. What is the value of the magnetic field inside it?

We have,

Current, I = 0.6 A

Number of turns in the solenoid, N = 6500

Length of solenoid, l = 25 cm = 0.25 m

The magnetic field inside the solenoid is given by :

B=\mu_o\dfrac{N}{l}I\\\\B=\dfrac{4\pi \times 10^{-7}\times 6500\times 0.6}{0.25}\\\\B=0.0196\ T

So, the value of the magnetic field inside the solenoid is 0.0196 T.

8 0
4 years ago
: why are energy and work measured using the same units?
Sedaia [141]
Because you have to have energy to have work.

6 0
3 years ago
Why is it that we can see blood cells only with a microscope? A) The cells form clumps. B) The cells keep moving about. C) The c
Snezhnost [94]
D the cells are very small
7 0
3 years ago
Read 2 more answers
A manometer using oil (density 0.900 g/cm3) as a fluid is connected to an air tank. Suddenly the pressure in the tank increases
Mila [183]

Answer:

Rise in level of fluid is 0.11 m

Rise in level of fluid in case of mercury is 0.728 cm or 7.28 mm

Solution:

As per the question:

Density of oil, \rho_{o} = 0.900\ g/cm^{3} = 900\ kg/m^{3}

Change in Pressure in the tank, \Delta P = 7.28\ mmHg

Density of the mercury, \rho_{m} = 13.6\ g/cm^{3} = 13600\ kg/m^{3}

Now,

To calculate the rise in the level of fluid inside the manometer:

We know that:

1 mmHg = 133.332 Pa

Thus

\Delta P = 7.28\ times 133.332 = 970.656\ Pa

Also,

\Delta P = \rho_{o} gh

where

g = acceleration due to gravity

h = height of the fluid level

970.656 = 900\times 9.8\times h

h = 0.11 m

Now, if mercury is used:

\Delta P = \rho_{m} gh

970.656 = 13600\times 9.8\times h

h = 0.00728 m = 7.28 mm

3 0
4 years ago
An alert physics student stands beside the tracks as a train rolls slowly past. He notes that the frequency of the train whistle
Dovator [93]

Answer:The velocity of the train is 3.84m/s

Explanation:

According to the Doppler effect, if the source is moving towards you then the apparent frequency of the sound emitted by the source is higher and if the source is moving away from you then the apparent frequency of the sound emitted by the source is smaller.

This is given by:

fo = V +-Vo/ V +-Vo × source

Where fo= observed frequency

V= velocity of sound

Vo= vo it of the observer

fsource= frequency the source

Given:

Observed frequency of the approaching train fo1= 452Hz

The observed frequency of train= fo2= 442Hz

Velocity of sound= 334m/s

Velocity of source=?

Train approaching the observer is given by:

fo1= V/(V - Vs)× source ...eq1

Train passes the student is given by:

fo2= V/(V - Vs)×source ...eq2

Divide eq1 by eq2

452/442 = (343+Vs)/(343 - Vs)

1.02 =(343+Vs)/(343 -Vs)

Cross multiply

1.02(343- Vs) = 343 + Vs

350.76 - 1.02Vs = 343 + Vs

Collecting like terms

350.76 -343= 1.02Vs+ Vs

7.76 = 2.02Vs

Vs= 7.76/2.02

Vs= 3.84m/s

4 0
3 years ago
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