Write a hypothesis for Part II of the lab, which is about the relationship described by F = ma. In the lab, you will use a toy c
2 answers:
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To solve this problem it is necessary to take into account the concepts related to electrochemical Machining Processes and metal removal. Metal removal rate is determined by Faraday's First law, which states that the amount of chemical change Produced by an electric current is proportional to the quantity of electricity passed, i.e,
Where,
V = Volume of material removed
C = Constant called the specific removal rate that depends on atomic weight (I attached a table with this values)
I = Current
t = time
Since we also have to consider the efficiency of the system to remove the Volume, of all the volume removed, only 95% will be efficient.
From our values we have to
Calculating the value we have that,
The area is simply the calculation of the total units by that of each piece, that is
Therefore we can calculate now the plating thickness through the ratio between Volume and Area
Therefore the average plating thickness on the parts is 0.000716in
Answer:
The angle of rotation given is incorrect, the correct function to have a balanced unit is
θ(t) = (1.10 rad/s)t + (6.30 rad/s²)t²
Explanation:
Given that,
Radius of disk is
R = 0.4m
Mass of disk
M = 30kg
The angle of rotation is a function of time and it is given as
θ(t) = (1.10 rad/s)t + (6.30 rad/s²)t²
What is linear angular acceleration "a" when it rotates 0.1rev
θ = 0.1 rev
1 rev = 2πrad
θ = 0.1 × 2πrad = 0.63 rad
Let calculate the time it revolves 0.63rad
θ(t) = (1.10 rad/s)t + (6.30 rad/s²)t².
0.63 = 1.1t + 6.3t²
6.3t² + 1.1t - 0.63 = 0
Solving this quadratic equation using formula method
t = [-b±√(b²-4ac)]/2a
a = 6.3 b = 1.1 c = -0.63
t = [-1.1 ± √(1.1²-4×6.3×-0.63)]/2×6.3
t = -1.1±√(1.21+15.876) / 12.6
t = -1.1 ± 4.13 / 12.6
Let discard the negative time
So, t = (-1.1 + 4.13) / 12.6
t = 0.24 s
Now,
Angular velocity can be determine using
ωz = dθ / dt
ωz = 1.1 + 12.6t, since t = 0.24
ωz = 1.1 + 12.6(0.24)
ωz = 4.124 rad/s
Angular acceleration can be determine using
αz = dωz/dt
αz = 12.6 rad/s²
The radial acceleration can be determined using
ar = ωz²•R
ar = 4.124² × 0.4
ar = 6.8 m/s²
Also, the tangential Acceleration is related to angular acceleration using
at = αz • R
at = 12.6 × 0.4
at = 5.04 m/s²
Then, the magnitude of the resultant acceleration can be calculated using
a = √(ar² + at²)
a = √(6.8² + 5.04²)
a = √71.64
a = 8.46 m/s²
Direction
β = Arctan(at/ar)
β = Arctan(5.04/6.8)
β = 36.54
This is the direction from the origin
But it has already revolve 0.1rev
1 rev = 360°
Then, θ = 0.1° = 360 × 0.1 = 36°
Direction = β — θ
Then, it direction is 36.54 — 54° = 0.54°
The direction is 0.54°
Check attachment for direction understanding
