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irakobra [83]
3 years ago
8

PLEASE HELP - Compare William and Jennifer's bank accounts (brainliest)

Mathematics
1 answer:
ad-work [718]3 years ago
3 0

Answer:

Jennifer in wrong. She is earning 12 dollars each week, whereas William is earning 14 dollars.

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_30. Solve the following logarithmic equation: log8(x + 9) + 3 = 3
Bezzdna [24]

Answer:

A

Step-by-step explanation:

using the rule of logarithms

log_{b} x = n ⇒ x = b^{n}

log_{8} (x + 9) + 3 = 3 ( subtract 3 from both sides )

log_{8} (x + 9) = 0 , then

x + 9 = 8^{0} = 1 ( subtract 9 from both sides )

x = - 8

7 0
2 years ago
Sum of 15 probability with two dice<br>​
Taya2010 [7]

Answer:

<h2>0</h2>

Step-by-step explanation:

all the outcomes you can get from rolling a dice twice are

2,3,4,5,6,7,8,9,10,11,12

15 is nowhere in those numbers so the probability of getting a sum of 15 is 0

6 0
3 years ago
Confused on this one
Fittoniya [83]

Answer:

It's probably D and E

Step-by-step explanation:

If wrong I'm sorry

3 0
3 years ago
Read 2 more answers
How much water does it take to completey fill a pool that is 50 m long, 25 m wide, and 2 m deep?
elixir [45]

Answer:

2500

Step-by-step explanation:

So it seems like we have to find the volume in this problem

The equation of volume it

lwh

Length · Width · Height

So all we do now is simply multiply.

50x25x2= 2500.

(Hope you find this helpful)

7 0
3 years ago
Find the smallest sample size n that will guarantee at least a 90% chance of the sample mean income being within $500 of the pop
Andreyy89

Answer:

The smallest sample size n that will guarantee at least a 90% chance of the sample mean income being within $500 of the population mean income is 48.

Step-by-step explanation:

The complete question is:

The mean salary of people living in a certain city is $37,500 with a standard deviation of $2,103. A sample of n people will be selected at random from those living in the city. Find the smallest sample size n that will guarantee at least a 90% chance of the sample mean income being within $500 of the population mean income. Round your answer up to the next largest whole number.

Solution:

The (1 - <em>α</em>)% confidence interval for population mean is:

CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}

The margin of error for this interval is:

MOE=z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}

The critical value of <em>z</em> for 90% confidence level is:

<em>z</em> = 1.645

Compute the required sample size as follows:

MOE=z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}

      n=[\frac{z_{\alpha/2}\cdot\sigma}{MOE}]^{2}\\\\=[\frac{1.645\times 2103}{500}]^{2}\\\\=47.8707620769\\\\\approx 48

Thus, the smallest sample size n that will guarantee at least a 90% chance of the sample mean income being within $500 of the population mean income is 48.

3 0
3 years ago
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