Answer:
Option B is correct.
Step-by-step explanation:
A = { 1, 3, 5, 7, 9 }
B = { 2, 4, 6, 8, 10 }
C = { 1, 5, 6, 7, 9 }
(B∩C) = {6} [Common element in set B and set C]
Now A∪(B∩C) = { 1, 3, 5, 6, 7, 9 }
Option B is the answer.
Answer:
80% of people carpool to work
Step-by-step explanation:
16/20 = .80
This is the best I got Require to make 2 equations with the same repeating part and subtract them to eliminate the repeating part.
begin by letting x = 0.5555555................. (1)
To obtain the same repeating part after the decimal point need to multiply by 10
hence 10x = 5.555555........................(2)
It is important to obtain 2 equations in x, where the recurring part after the decimal points are exactly the same.
now subtract (1) from (2) to obtain fraction
(2) - (1) : <span>9x=5⇒x=<span><span>59</span></span></span>
Answer:
2x^2- 8x
Step-by-step explanation:
2x(x-4)
distribute; multiply parenthesis by 2 x
2x * x-2x *4
calculate products
2x^2- 8x
Let's assume that the statement "if n^2 is odd, then is odd" is false. That would mean "n^2 is odd" leads to "n is even"
Suppose n is even. That means n = 2k where k is any integer.
Square both sides
n = 2k
n^2 = (2k)^2
n^2 = 4k^2
n^2 = 2*(2k^2)
The expression 2(2k^2) is in the form 2m where m is an integer (m = 2k^2) which shows us that n^2 is also even.
So this contradicts the initial statement which forces n to be odd.
