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lana [24]
3 years ago
15

What are the

Mathematics
1 answer:
mario62 [17]3 years ago
5 0

Answer:

x = 1+√83 i/6 and 1-√83 i/6

Step-by-step explanation:

Given the quadratic expression;

3x^2-x+7 =0

Using the general foemula to find x

x = -b±√b²-4ac/2a

From the equation

a = 3, b = -1 and c = 7

Substitute

x = -(-1)±√(1)²-4(3)(7)/2(3)

x = 1±√1-84/6

x = 1±√-83/6

x = 1±√83 i/6

x = 1+√83 i/6 and 1-√83 i/6

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Three investors own a company. One partner owns One-fourthof the company, while the second partner owns Two-fifths of the compan
Lelechka [254]

Answer:

7/20

Step-by-step explanation:

2/5 = 8/20

1/4 = 5/20

20/20 - 13/20 = 7/20

5 0
3 years ago
I need help, someone please explain. I don't need the answers i just don't get it.
shepuryov [24]
What answers well whats the question?
4 0
3 years ago
Help geometry what I m jlf <br> Picture provided
Zolol [24]

Answer:

\angle\,JLF = 114^o  which agrees with option"B" of the possible answers listed

Step-by-step explanation:

Notice that in order to solve this problem  (find angle JLF) , we need to find the value of the angle defined by JLG and subtract it from 180^o, since they are supplementary angles. So we focus on such, and start by drawing the radii that connects the center of the circle (point "O") to points G and H, in order to observe the central angles that are given to us as 90^o and 138^o. (see attached image)

We put our efforts into solving the right angle triangle denoted with green borders.

Notice as well, that the triangle JOH that is formed with the two radii and the segment that joins point J to point G, is an isosceles triangle, and therefore the two angles opposite to these equal radius sides, must be equal. We see that angle JOH can be calculated by : 360^o-90^o-138^o=132^o

Therefore, the two equal acute angles in the triangle JOH should add to:

180^o-132^o=48^o resulting then in each small acute angle of measure 24^o.

Now referring to the green sided right angle triangle we can find find angle JLG, using: 180^o-24^o-90^o=66^o

Finally, the requested measure of angle JLF is obtained via: 180^o-66^o=114^o

4 0
3 years ago
What is 75 + 15x ≥ 140
melomori [17]
75+ 15x ≥ 140
⇒ 15x ≥ 140-75
⇒ 15x ≥ 65
⇒ x ≥ 65/15
⇒ x ≥ 13/3
⇒ x ≥ 4 1/3

Final answer: x ≥ 4 1/3~
8 0
3 years ago
In AJKL, JL is extended through point L to point M, m m
arlik [135]

Answer:

x = 15

Step-by-step explanation:

The exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.

∠ KLM is an external angle of the triangle, thus

∠ KLM = ∠ JKL + ∠ KJL , substitute values

5x - 7 = x + 20 + 2x + 3

5x - 7 = 3x + 23 ( subtract 3x from both sides )

2x - 7 = 23 ( add 7 to both sides )

2x = 30 ( divide both sides by 2 )

x = 15

4 0
3 years ago
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