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lana [24]
3 years ago
8

for a certain company, the cost function for producing x items is C(x)=40x+150 and the revenue function for selling x items is R

(x)=-0.5(×-110)^2+6,050. the maximum capacity of the company is 160 items.​
Mathematics
1 answer:
Mademuasel [1]3 years ago
5 0

Answer  :

Step-by-step explaation:

c(80) =40x80 +150 =3350  üretim için 80  parçanın maliyeti

satış için ise : R(80) 0.5(80-110)^2+6,050 =  456

3350-456=2983.95 kar ederler  

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Determine the common ratio and find the next three terms of the geometric sequence 9,3sqrt3,3
Maru [420]

Answer:

Fourth term: a_4 = 9 * (\frac{\sqrt{3}}{3})^{(4 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{3} = \sqrt{3}

Fifth term: a_5 = 9 * (\frac{\sqrt{3}}{3})^{(5 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{4} = 1

Sixth term: a_6 = 9 * (\frac{\sqrt{3}}{3})^{(6 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{5} =\frac{\sqrt{3}}{3}

Step-by-step explanation:

The geometric progression is:

9, 3 \sqrt{3}, 3...

The first term, a, is 9

To find the common ratio, r, all we have to do is divide a term by its preceding term.

Let us divide the second term by the first:

r = \frac{3\sqrt{3}}{9}\\ \\r = \frac{\sqrt{3}}{3}

That is the common ratio.

Geometric progression is given generally as:

a_n = ar^{(n - 1)}

where a = first term

r = common ratio

a_n = nth term

We need to find the 4th, 5th and 6th terms.

Fourth term: a_4 = 9 * (\frac{\sqrt{3}}{3})^{(4 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{3} = \sqrt{3}

Fifth term: a_5 = 9 * (\frac{\sqrt{3}}{3})^{(5 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{4} = 1

Sixth term: a_6 = 9 * (\frac{\sqrt{3}}{3})^{(6 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{5} =\frac{\sqrt{3}}{3}

5 0
3 years ago
What number must multiply each side of the equation 25x=10 to produce the equivalent equation x = 25?
insens350 [35]

Answer:

Multiply both sides by \frac{5}{2}

Step-by-step explanation:

Given

\frac{2}{5}x = 10

Required

Get an equivalent of x = 25

To do this, we simply multiply through by \frac{5}{2}

\frac{5}{2} * \frac{2}{5}x = 10 * \frac{5}{2}

\frac{5*2}{2*5} x = 10 * \frac{5}{2}

\frac{10}{10} x = 10 * \frac{5}{2}

\frac{1}{1} x = 10 * \frac{5}{2}

x = 10 * \frac{5}{2}

x =\frac{10*5}{2}

x =\frac{50}{2}

x = 25

5 0
3 years ago
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dolphi86 [110]

Answer:

The answer is A, $330

Step-by-step explanation:

8 0
3 years ago
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XY and BD are parallel lines
Leto [7]

Answer:

Step-by-step explanation:

Given that,

XY//BD and XB=XC

Since, XB = XC, then ∆XBC is an isosceles triangle with angle <B = <C.

A. If an angle occupy the same relative position at each intersection where a straight line crosses two others straight lines. If the two straight lines are parallel, then the corresponding angles are equal.

To check for corresponding angle: look at if the shape form "F" shape and be sure that the lines that form the "F" shape are parallel.

So, to complete the statement,

Angle XBC = 55° because it a corresponding angle to AXY

They form a "F" and XY//BD

B. To find BXC

We know that triangle BXC is an isosceles triangle

The sum of angle in a triangle is 180°

Then,

XBC + BCX + BXC = 180°

Since, ∆XBC is isosceles then, angle <XBC = < BCX = 55°

Then,

XBC + BCX + BXC = 180°

55 + 55 + BXC = 180°

110 + BXC = 180°

BXC = 180° - 110

BXC = 70°

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3 years ago
I need help to match them
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7 is the third one. 8 is the first one. 9 is the second one.
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