See the attached figure
radius of the circle = r = 6
the length of one side of the equilateral triangle = L
the height if the triangle = h
The shaded area is the required area.
∴The area = (1/3) (area of circle - area of triangle )
area of circle = π r² = π * 6² = 36 π
An equilateral triangle is inscribed in a circle of radius r
∴ The length of one side of the triangle = √3 * r
= 6√3
and the height of the triangle = (√3 /2) * 6√3 = 9
∴ Area of the triangle = 0.5 * 9 * 6√3 = 27√3
The required area = (1/3) (area of circle - area of triangle )
= (1/3) * ( 36π - 27√3 )
= 12π - 9√3
Answer:
Step-by-step explanation:
hello :
tanx = √3 0°≤x≤360°
x = 60°
x=240°
Answer:
the height of the flagpole is three fourths the height of the school. the difference in there heights is 4.5 m. what is the height of the school?
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Equation:
f = (3/4)s
s-f = 4.5
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Substitute for "f" and solve for "s":
s-(3/4)s = 4.5
(1/4)s = 4.5
s = 4*4.5
s = 18 meters (height of the school)
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Since f = (3/4)s, f = (3/4)(18)
= (3/2)(9)= 13.5 meters (height of the flag pole)
===============================-step explanation: HOPE THIS HELPS