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3 years ago

9

Segment AB and Segment CB are tangent to circle E. Which is NOT a property that can be used to prove that triangles ABD and CBD

congruent?
A) AA
B) ASA
C) AAS
D) SSS

2 answers:

egoroff_w [7]3 years ago

4 0

Answer:

Step-by-step explanation:

THE ANSWER MUST BE A)AA because that was the only one that not fix into the graph.

ollegr [7]3 years ago

4 0

Answer with explanation:

Two triangles are congruent,by the following Postulates :

1. A SA→→Angle Side Angle

2. A A S→→→Angle Angle Side

3. S S S→→Side Side Side

4.SA S→→Side Angle Side

The two triangles are not congruent by

When either two angles of one triangle or Three angles of one triangle are equal to two angles or three angles of another triangle called AA or AAA.

→→ΔA B D is not≅ to ΔC B D ,by AA.

Option A: ⇒A A

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How many ways can a dance instructor send 4 of her 11 students to a summer dance program?

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Answer:

d) 330

Step-by-step explanation:

The number of ways can a dance instructor send 4 of her 11 students to summer dance program is C(11 , 4)

That is $11_{C_{4} }$ ways

by using formula $n_{C_{r} } = \frac{n!}{(n-r)!r!}$

now simplification

$11_{C_{4} } = \frac{11!}{(11-4)!4!}$

= $\frac{11X10X9X8X7!}{(7!)4X3X2X1}$

after cancelling 7! and on simplification

= $\frac{11X10X9X8}{4X3X2X1}$

after cancellation we get 330 ways

The number of ways can a dance instructor send 4 of her 11 students to summer dance program is 330

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3 years ago

1,729 is divisible by 9<br> a. true<br> b. false

alexgriva [62]

It is b: False 1,729 isn’t divisible by 9

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2 years ago

Please help!! What Find the Error and explain why it is wrong!

Nata [24]

Answer:

First image attached

The error was done in Step E, because student did not multiply $2\cdot x -8$ by the negative sign in numerator. Step E must be $\frac{2\cdot x -5}{(x+4)\cdot (x-4)}$ .

Second image attached

The error was done in Step C, because the student omitted the $2\cdot a \cdot b$ of the algebraic identity $(a+b)^{2} = a^{2}+2\cdot a\cdot b +b^{2}$ . Step C must be $5\cdot x = x^{2}+4\cdot x + 4$

Step-by-step explanation:

First image attached

The error was done in Step E, because student did not multiply $2\cdot x -8$ by the negative sign in numerator. The real numerator in Step E should be:

$3-(2\cdot x -8)= 3-2\cdot x+8 = 11-2\cdot x$

Hence, Step E must be $\frac{2\cdot x -5}{(x+4)\cdot (x-4)}$ .

Second image attached

The error was done in Step C, because the student omitted the $2\cdot a \cdot b$ of the algebraic identity $(a+b)^{2} = a^{2}+2\cdot a\cdot b +b^{2}$ . Step C must be $5\cdot x = x^{2}+4\cdot x + 4$

And further steps are described below:

Step D

$x^{2}-x+4 = 0$

Which according to the Quadratic Formula, represents a polynomial with complex roots. That is: ( $a = 1$ , $b = -1$ , $c = 4$ )

$D = b^{2}-4\cdot a\cdot c$

$D = (-1)-4\cdot (1)\cdot (4)$

$D = -17$ (Conjugated complex roots)

Step E

$(x-0.5-i\,1.936)\cdot (x-0.5+i\,1.936) = 0$

Step F

$x = 0.5+i\,1.936\,\lor\,x = 0.5-i\,1.936$

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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2 years ago

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