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lutik1710 [3]
3 years ago
9

Segment AB and Segment CB are tangent to circle E. Which is NOT a property that can be used to prove that triangles ABD and CBD

congruent?
A) AA
B) ASA
C) AAS
D) SSS
Mathematics
2 answers:
egoroff_w [7]3 years ago
4 0

Answer:

Step-by-step explanation:

THE ANSWER MUST BE A)AA because that was the only one that not fix into the graph.

ollegr [7]3 years ago
4 0

Answer with explanation:

Two triangles are congruent,by the following Postulates :

1. A SA→→Angle Side Angle

2. A A S→→→Angle Angle Side

3. S S S→→Side Side Side

4.SA S→→Side Angle Side

The two triangles are not congruent by

When either two angles of one triangle or Three  angles of one triangle are equal to  two angles or three angles of another triangle called AA or AAA.

→→ΔA B D is not≅ to ΔC B D ,by AA.

Option A: ⇒A A

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It's very urgent plss answer
Lesechka [4]

The solution of the equation 4p – [(2p – 3) / 2] = 6 with variable p will be 1.5.

<h3>What is the solution of the equation?</h3>

The solution of the equation means the value of the unknown or variable.

The equation is given below.

4p – [(2p – 3) / 2] = 6

On simplifying, we have

(8p – 2p + 3) / 2 = 6

               6p + 3 = 12

                     6p = 9

                       p = 1.5

More about the solution of the equation link is given below.

brainly.com/question/545403

#SPJ1

8 0
1 year ago
Simplify:- ~~~~~~~
Alchen [17]

\sf \dashrightarrow \:  -  \frac{2}{5}  - ( -  \frac{3}{10} ) - ( -  \frac{4}{7} )

When there is a - in front of an expression in parentheses, change the sign of each term in the expression to +

\sf \dashrightarrow \:  -  \frac{2}{5}    + \frac{3}{10}  +  \frac{4}{7}

Calculate the LCM of denominators

\sf\frac{ - 28 + 21 + 40}{70}

Calculate the difference

\bf \underline{ \underline \frac{33}{70} }

7 0
2 years ago
Read 2 more answers
61. A survey asked students what classes they
IRISSAK [1]

Answer:

63 students.

Step-by-step explanation:

x students.

34 have science 28 have math 5 math and science 6 neither.

6 neither means there were at least 6 students so our number goes up to 6 students.

34 have science 28 have math 5 have both.

34-5 and 28-5

29 and 23

29+23 is 52 +5 is 57 +6 is 63.

63 students.

HOpe this helps!

Merry Christmas!

4 0
3 years ago
Read 2 more answers
Find the base of a parallelogram with a slant height of 7cm and an perimeter of 63 cm2
vlada-n [284]

Base of parallelogram b = 24.5 cm

Step-by-step explanation:

We are given:

Perimeter =P= 63 cm^2

Slant Height =a= 7 cm

Base of Parallelogram =b= ?

The formula used is:

Perimeter = 2(a+b)

where a is height and b is base

Putting values:

Perimeter = 2(a+b)\\63=2(7+b)\\63=14+2b\\2b=63-14\\2b=49\\b=\frac{49}{2}\\b=24.5

So, Base of parallelogram b = 24.5 cm

Keywords: Perimeter of Parallelogram

Learn more about Perimeter of Parallelogram at:

  • brainly.com/question/6594923
  • brainly.com/question/1822996
  • brainly.com/question/6594923

#learnwithBrainly

5 0
3 years ago
Calcula y comprueba las ecuaciones: porfavor alguienn la nesesito pliss a) 2X = 6 b) 10 + Z = 20 c) P + 9 = 11 d) 3X + 8 = + 29
Alexeev081 [22]

Answer:

<u>a) x = 3</u>

<u>b) z = 10</u>

<u>c) p = 2</u>

<u>d) x = 7</u>

<u>e) u = 1</u>

Step-by-step explanation:

a) 2x = 6

Despejamos x dividiendo por 2 a amabos lados de la eacuacion.

(2/2)x = 6/2

<u>x = 3</u>

Si remplazamos x en la ecuación original:

2(3)=6

6 = 6

Queda demostrado.

b) 10 + z = 20

Despejamos z restando 10 en amabos lados de la eacuacion.

10-10+z = 20-10

<u>z = 10</u>

Si remplazamos z en la ecuación original:

10 + 10=20

20 = 20

Queda demostrado.

c) p + 9 = 11

Despejamos p restando 9 en amabos lados de la eacuacion.

p + 9 - 9 = 11-9

<u>p = 2</u>

Si remplazamos p en la ecuación original:

2 + 9 = 11

11 = 11

Queda demostrado.

d) 3x + 8 = 29

Despejamos x restando 8 en amabos lados de la eacuacion y luego divideindo por 3 en ambos lados de la ecuación.

3x+8-8 = 29-8

3x = 21

(3/3)x = 21/3

<u>x = 7</u>

Si remplazamos x en la ecuación original:

3(7) + 8 = 29

21 + 8 = 29

29 = 29

Queda demostrado

e) 2u + 8 = 10

Despejamos u restando 8 en amabos lados de la eacuacion y luego divideindo por 2 en ambos lados de la ecuación.

2u+8-8 = 10-8

2x = 2

(2/2)x = 2/2

<u>x = 1</u>

Si remplazamos x en la ecuación original:

2(1) + 8 = 10

2 + 8 = 10

10 = 10

Queda demostrado

Espero te haya sido de ayuda!

5 0
2 years ago
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