Difference of 2 perfec squares is
(a^2)-(b^2)
if the exponents are both even and the coeficient (the number in front) are perfect squares, then it is difference t 2 perfect squares
first one
8 is not perfect square
2nd one
(4e^4)^2-(9g^2)^2
third
25 is odd, so it cannot be split up into 2 nice numbers
4th
(11m^9)^2-(3n^5)^2
I think your teacher's just asking for the multiplied out version, so there's no work to do
3. -2(3m + 9) = -6m - 11
4. -6(z-1) = -6z + 6
5. -(m +1) = -m - 1
6. -(x+4) = x = 4
7. b(a- 6) = ab - 6b
8. 7a(3b -2c + 4) = 21ab - 14ac +28a
9. 1/2(8x + 2) = 4x + 1
10. 2/3(1/4x -6) = 1/6x - 4
It's 3.3 because the 2 is in the tenths place and you look at 6 and say is it over 5? Yes it is so the next number after 2 is 3 so your answer is 3.3
#1 : ( 3 , - 2 )
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#2 : ( - 1 , 4 )
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I hope that helps you out!!
Any more questions, please feel free to ask me and I will gladly help you out!!
~Zoey
Answer:
yes the statement is true
Step-by-step explanation:
if you plug in 1^2 you are just multiplying 1 by its self
