1. y = -x - 2...slope here is -1. A parallel line will have the same slope
y = mx + b
slope(m) = -1
(2,-2)...x = 2 and y = -2
now we sub and find b, the y int
-2 = -1(2) + b
-2 = -2 + b
-2 + 2 = b
0 = b
so ur parallel equation is : y = -x
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2. -1 = -3/2(2) + b
-1 = -3 + b
-1 + 3 = b
2 = b
parallel equation is : y = -3/2x + 2
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3. parallel equation is : x = 4
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4. 3 = 1/2(-2) + b
3 = -1 + b
3 + 1 = b
4 = b
parallel equation is : y = 1/2x + 4
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5. y + 0 = 2(x - 5)
y = 2x - 10 <== parallel line
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6. neither
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7. if ur second equation is : 2x + y = 7, then the lines are parallel
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8. neither
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9. sometimes
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10. never
4Step-by-step explanation:
bhtrrerh
Answer:
see explanation
Step-by-step explanation:
Using the trigonometric identity
sin²x + cos²x = 1
Consider the left side
2cos²A - 1 ← replace 1 by sin²A + cos²A
= 2cos²A - ( sin²A + cos²A)
= 2cos²A - sin²A - cos²A
= cos²A - sin²A = right side ⇒ verified
