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3 years ago

Can someone please answer some of my questions? *They are all math

Mathematics

2 answers:

natulia [17]3 years ago

6 0

What grade and maybe i’m only in 8th tho

Step2247 [10]3 years ago

3 0

Answer:

DA FA WERE ARE THE QUESTIONS?????????

Step-by-step explanation:

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What is the solution to this equation?

Radda [10]

Answer:

9. This is because you have to add 13 to -4, which gives you positive 9. Hope this helped!

5 0

3 years ago

Write and evaluate the expression. Then, select the correct answer. The sum of forty-five and a number; evaluate when n = 1. 1 4

Colt1911 [192]

The sum of forty-five and a number n is 46.1, and the expression that can represent this can be written "45+n" where the value of n is 1.1

<h3>What is an Expression?</h3>

In mathematics, an expression is defined as a set of numbers, variables, and mathematical operations formed according to rules dependent on the context.

The statement that is given to us is" the sum of forty-five and a number", therefore, the expression that will represent this can be written as,

45 + n,

Now, if the value of n is 1.1. Then the sum will be,

$45+n\\\\=45+1.1\\\\=46.1$

Hence, the sum of forty-five and a number n is 46.1, and the expression that can represent this can be written "45+n" where the value of n is 1.1

Learn more about Expression:

brainly.com/question/13947055

6 0

2 years ago

10) Show that in a group of 10 people (where any two people are either friends or enemies), there are either three mutual friend

ddd [48]

Answer with explanation:

Number of People in the group =10 People

The combination between two people is that, they can be either friends or enemies.

Total number of Possible Relation

=18 +16+14+12+10+8+6+4+2

= 90 Relations in all.

Out of 90 relations , 45 will be friends and 45 will be enemies.

⇒Now, we have to prove that, between 10 people, there are either three mutual friends or four mutual enemies, and there are either three mutual enemies or four mutual friends.

→→If there are three mutual friends, total number of people in the group =3 ×2=6 people in the group

And, four mutual enemies in a group means there are 2 people in each group.

So, total number of people if we combine the two groups in which there are either three mutual friends or four mutual enemies

=6 +4

=10

Hence proved.

→→→→Second part is ,in this group there can be either three mutual enemies or four mutual friends.

⇒If there are three mutual enemies, total number of people in the group =3 ×2=6 people in the group

And, four mutual friends in a group means there are 2 people in each group.

So, total number of people if we combine the two groups in which there are either three mutual enemies or four mutual enemies

=6 +4

=10

Hence proved.

3 0

3 years ago

Observe the equation below, can a value be found for x to make the equation true? Why or why not? 0=4x

Fiesta28 [93]

You have written 0 = 4x.

The value of x that makes it true is x = 0, given that 4 times 0 is 0.

Nevertheless, I think you wanted to write 0 = 4 ^x (this is 4 raised to the power 4).

In that case, there is not any valued of x that satisfies the equation. This is, the equation is always false.

That is because, there is not any value of x for which 4^x is zero. The range of this function is al the positive values of x, which exclude zero.

3 0

3 years ago

The graph of y = f(x) is shown below. What are all of the real solutions of f(x) = 0?

bonufazy [111]

Answer:

the real solutions are the ones that actually cross the x-axis.

so the real solutions are (-5, 0) (-1,0) (4,0) and (8,0)

5 0

3 years ago