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Flauer [41]
3 years ago
15

What is the y-intercept on the equation: y= 3/4x - 1

Mathematics
1 answer:
Ket [755]3 years ago
7 0
-1 is the y intercept
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Can someone find the surface area for this? :)
AysviL [449]

Answer:

84 :)

Step-by-step explanation:

bottom surface area= 6m^{2}

top surface area=6m^{2}

lateral surface area= 72m^{2}

add this together you get TOTAL surface area of 84

3 0
3 years ago
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Find the unknown length in the right triangle 27cm and 13 cm
Phoenix [80]

use pythagoras:

{c}^{2}  = \:   {b}^{2}  -  {a}^{2}

c^2 = (27)^2 - (13)^2

c^2 = 560

c = 23.6643....cm

3 0
3 years ago
It says solve by factoring.
dsp73

Answer:

Alright well Graph each side of the equation. The solution is the x - value of the point of intersection k = 4.582 Hope this helps :)

Step-by-step explanation:


6 0
3 years ago
Read 2 more answers
Please Help..............
Anvisha [2.4K]
Well to do scientific notation u have to use 10 then an exponent 
example: 
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so u need exponents to do scientific notation.
7 0
3 years ago
Use the Fundamental Theorem of Calculus to find the area of the region between the graph of the function x5 + 8x4 + 2x2 + 5x + 1
belka [17]

Answer:

The area of the region between the graph of the given function and the x-axis = 25,351 units²

Step-by-step explanation:

Given  x⁵ + 8 x⁴ + 2 x² + 5 x + 15

If 'f' is a continuous on [a ,b] then the function

            F(x) = \int\limits^a_b {f(x)} \, dx

By using integration formula

\int{x^n} \, dx = \frac{x^{n+1} }{n+1} +c

Given  x⁵ + 8 x⁴ + 2 x² + 5 x + 15 in the interval [-6,6]

 \int\limits^6_^-6} (x^{5}  + 8 x^{4}  + 2 x^{2}  + 5 x + 15) )dx

<em>On integration , we get</em>

=   (\frac{x^{6} }{6} + \frac{8 x^{5} }{5} + 2 \frac{x^{3} }{3} +\frac{5 x^{2} }{2} + 15 x)^{6} _{-6}

F(x) = \int\limits^a_b {f(x)} \, dx = F(b) -F(a)

= (\frac{6^{6} }{6} + \frac{8 6^{5} }{5} + 2 \frac{6^{3} }{3} +\frac{5 6^{2} }{2} + 15X 6) - ((\frac{(-6)^{6} }{6} + \frac{8 (-6)^{5} }{5} + 2 \frac{(-6)^{3} }{3} +\frac{5 (-6)^{2} }{2} + 15 (-6))

After simplification and cancellation we get

 =  \frac{2 X 8 X (6)^{5} }{5} + \frac{2 X 2 X (6)^3}{3} + 2 X 15 X 6

on calculation , we get

= \frac{124,416}{5} + \frac{864}{3} + 180

On L.C.M  15

= \frac{124,416 X 3 + 864 X 5 + 180 X 15}{15}

= 25 351.2 units²

<u><em>Conclusion</em></u>:-

<em>The area of the region between the graph of the given function and the x-axis = 25,351 units²</em>

6 0
3 years ago
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