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quester [9]
3 years ago
10

Can you help me with this?

Mathematics
2 answers:
Ira Lisetskai [31]3 years ago
5 0

Answer:

30

Step-by-step explanation:

The area formula for trapezoid- A=1/2*h*(b1+b2)

So- 1/2*4*(6+9)

Ugo [173]3 years ago
4 0

Answer:

B =30 yd²

Step-by-step explanation:

total area

= area of rectangle + area of triangle

=(6*4)+(1/2 * 3 * 4)

=30

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48.76+20.08=20.08+ n
Slav-nsk [51]

Answer:

I got n=48.76

Step-by-step explanation:

Solve for n by simplifying both sides of the equation then isolating the variable. I hope this helps  

7 0
4 years ago
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Help me please how to solve y=1/2x-6
Dvinal [7]
Y=(1/2)x-6 and solving for x.
So first you bring the 6 to the other side: y+6=(1/2)x
Then you divide by (1/2) to isolate the x (y+6)/(1/2)=x
This simplifies to 2(y+6)=x    because dividing by one half is the same as multiplying by 2
Hope this helps :)
4 0
3 years ago
Jack looks at a clock tower from a distance and determines that the angle of elevation of the top of the tower is 40°. John, who
Artemon [7]
I would say 25.50 meters. Hope this helps!
6 0
4 years ago
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What is the product in scientific notation?
sashaice [31]
(2.5 × 10^{-10} ) × (7 × 10^{-6} )

First, simplify brackets. / Your problem should look like: 2.5 × 10^{-10} × 7 × 10^{-6}
Second, simplify. / Your problem should look like: 17.5 × 10^{-10} × 10^{-6}
Third, simplify exponent. / Your problem should look like: 17.5 × 10^{-15}

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3 0
3 years ago
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An elementary school is in a growing suburb. The school’s principal estimates that the current enrollment of 750 students will i
HACTEHA [7]

Answer:

62.9% in ten years

Step-by-step explanation:

This type of growth corresponds to what is called an exponential growth, since in the expression for the number of students keep including the multiplication of the same factor as the years go by, Let's start by analyzing what happens the first year:

The initial enrollment of 750 is expected to grow by 5%, therefore after one year the enrollment should be:

After one year = Year_1 = 750 + 5% increase = 750+750*0.05=750(1+0.05)

where we have used the decimal form of 5% as he factor 0.05 multiplying 750 (the initial enrollment) to give the increase.

After the second year, we consider a starting value of Year_1 enrollments that will increase another 5%, which gives: Year_2 = Year_1 + Year_1 * 0.05= Year_1 (1 + 0.05).

So replacing Year_1 by its original expression (750(1+0.05)) we notice that Year_2 = 750 * (1+0.05) * (1+0.05) = 750 * (1+0.05)^2

We can go on with this same reasoning and find that each year includes a new factor (1+0.05) to the new increasing enrollment.

At the end of 10 years, the number of enrollment will be:

750*(1+0.05)^10=1221.67

which we can round to 1222 students enrolled

This means and increase of: \frac{1222-750}{750} =0.62933

That is approximately 62.9%

6 0
3 years ago
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