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3 years ago

Find the equation of a line that is parallel to line g that contains (P, Q).

Mathematics

2 answers:

Fofino [41]3 years ago

8 0

Correct option:

$\boxed{x-y=P-Q}$

<h2>Explanation:</h2>

Given that the line we are looking for is parallel to g, then the slope of that line and g is the same, therefore:

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\ \\ (x_{1},y_{1})=(-3,2) \\ \\ (x_{2},y_{2})=(0,5) \\ \\ \\ m=\frac{5-2}{0-(-3)}=1$

So we can write the point-slope form of the equation of the line as follows:

$y-y_{0}=m(x-x_{0}) \\ \\ (x_{0},y_{0})=(P,Q) \\ \\ \\ y-Q=1(x-P) \\ \\ y-Q=x-P \\ \\ \\ Arranging: \\ \\ P-Q=x-y \\ \\ \boxed{x-y=P-Q}$

<h2>Learn more:</h2>

Graphying systems of linear equations: brainly.com/question/13799715

#LearnWithBrainly

Lorico [155]3 years ago

3 0

Answer:

X - Y = P - Q

Step-by-step explanation:

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