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Vesnalui [34]
2 years ago
11

Help me plz don’t get it

Mathematics
2 answers:
Andrei [34K]2 years ago
8 0

Answer:

$200.75

Step-by-step explanation:

Brainliest please

Rudik [331]2 years ago
3 0
The answer is 200.75 dollars
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X/-4 + 14&gt;20<br><br> someone help a girl out
MrRa [10]

Answer:

x < -20

Step-by-step explanation:

x / -4  + 14 >20

Subtract 14 from each side

x / -4 +14-14 > 20 -14

x / -4 > 6

Multiply each side by -4, remembering to flip the inequality

x / -4 * -4 < 6 * -4

x < -20

7 0
2 years ago
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What is the value of the function at x = 3?<br><br> Enter your answer in the box.
butalik [34]

Answer:

4

Step-by-step explanation:

Recall a linear function, is a line on a graph made up of an infinite amount of points which satisfy the relationship. That means at x=3 there is a specific point on the line with an output. The value of a function at x=3 asks, what is the output y value for the input x value?

To find it, we locate 3 on the x-axis. We draw a vertical line directly to the line following the grid line. We mark the point on the line. We then draw a horizontal line directly to the y-axis following the grid line. The point we hit on the y-axis is the value of the function.

Here it is 4.

3 0
3 years ago
I have 100 items of product in stock. The probability mass function for the product's demand D is P(D=90)=P(D=100)=P(D=110)=1/3.
masya89 [10]

Answer:

The probability mass function for the items sold is

P_X(k) = \left \{ {\frac{1}{3} \, \, \, {k=90} \atop \, \frac{2}{3} \, \, \, {k=100}} \right.

The mean is 96.667

The variance is 22.222

b) The probability mass function for the unfilled demand due to lack of stock is

P_Y(k) = \left \{ {\frac{2}{3} \, \, \, {k=0} \atop \, \frac{1}{3} \, \, \, {k=10}} \right.

The mean is 3.333

The variance is 33.333

Step-by-step explanation:

If the demand is higher than 100, then you will sell 100 items only. Thus, there is a probability of 1/3+1/3 = 2/3 that you will sell 100 items, while there is a probability of 1/3 that you will sell 90.

The probability mass function for the items sold is

P_X(k) = \left \{ {\frac{1}{3} \, \, \, {k=90} \atop \, \frac{2}{3} \, \, \, {k=100}} \right.

The mean is 1/3 * 90 + 2/3 * 100 = 290/3 = 96.667

The variance is V(X) = E(X²)-E(X)² = (1/3*90² + 2/3*100²) - (290/3)² = 200/9 = 22.222

b) If order to be unfilled demand, you need to have a demand of 110, which happens with probability 1/3. In that case, the value of the variable, lets call it Y, that counts the amount of unfilled demand due to lack of stock is 110-100 = 10. In any other case, the value of Y is 0, which would happen with probability 1-1/3 = 2/3. Thus

P_Y(k) = \left \{ {\frac{2}{3} \, \, \, {k=0} \atop \, \frac{1}{3} \, \, \, {k=10}} \right.

The mean is 2/3 * 0 + 1/3 * 10 = 10/3 = 3.333

The variance is 2/3*0² + 1/3*10² = 100/3 = 33.333

4 0
2 years ago
A vertical line has points C, E, F from top to bottom. 2 lines extend from point E. One line extends to point A and another exte
mariarad [96]

Answer:

A.D.E

I GOT IT RIGHT IN EDG

7 0
2 years ago
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What is 0.8 repeating times 88
vichka [17]

0.\overline{8}=\dfrac{8}{9}\\\\0.\overline{8}\cdot88=\dfrac{8}{9}\cdot88=\dfrac{704}{9}=78.\overline{2}

6 0
3 years ago
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