Louann= 14x+24
Carla= 16x+14
So basically this is just like solving equations. The way I did this was just put random numbers for x and then solve it.
First attempt:
14(7)+24=16(7)+14
98+24=112+14
122=126
Okay the first one didn't work so I use 6 for x.
Second attempt:
14(6)+24=16(6)+14
84+24=96+14
108=110
So 6 didn't work and you already should know that the answers should be between 1 and 5.
So now I going to do 5 for x
Third attempt:
14(5)+24=16(5)+14
70+24=80=14
94=94
And so the answer is 5! :D The multiply choice questions were worth 5 points and Louann and Carla had 94 for their scores! I hope this help you out and clear for you! :D
Answer:
answer is choice 4 because in te given angle A and angle B are congrunt and if they are acute the degree measure is 0-90
Circle: x^2+y^2=121=11^2 => circle with radius 11 and centred on origin.
g(x)=-2x+12 (from given table, find slope and y-intercept)
We can see from the graphics that g(x) will be almost tangent to the circle at (0,11), and that both intersection points will be at x>=11.
To show that this is the case,
substitute g(x) into the circle
x^2+(-2x+12)^2=121
x^2+4x^2-2*2*12x+144-121=0
5x^2-48x+23=0
Solve using the quadratic formula,
x=(48 ± √ (48^2-4*5*23) )/10
=0.5058 or 9.0942
So both solutions are real and both have positive x-values.
The hundredth is the second number to the right of the decimal point. Also, if the number directly to the right of it is 5 or larger, you will have to round up by one.
23.558 becomes 23.56.
8 divide by 5
X=4-3 and that's the right answer
Thank you
