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Paladinen [302]
3 years ago
14

The quotient of nine times a number and seven ?

Mathematics
1 answer:
IRISSAK [1]3 years ago
7 0
9/7n is the answer i am pretty sure
You might be interested in
4^x+7 = 8^2x-3 Solve each equation showing work please
RUDIKE [14]

If 4=2^2

8=2^3

(2^)2x+10=(2^)6x

(2^)6x-(2^)2x=10

(2^)2x×7=10, where x has no real value

3 0
3 years ago
For what value of c is the relation a function? {(2.8). (12.3).(c.4), (-1.8). (0.3}}
raketka [301]

Answer:  B) 1

=======================================================

Explanation:

I'm assuming you were given the list of points to be

{(2,8). (12,3).(c,4), (-1,8). (0,3}}

the x coordinates of each point are: 2, 12, c, -1 and 0

If c is equal to any of the other x coordinates (2, 12, -1, or 0), then this will mean we have a repeated x coordinate. In turn, this leads to us not having a function.

---------

Consider the case that c = 2.

This means that (2,8) and (2,4) are two points in this relation. The input x = 2 leads to multiple outputs y = 8 and y = 4 at the same time. A function is not possible here. A function is only possible if we have any given input lead to exactly one output only. So this is why c = 2 is not possible if we want a function. The same goes for the other x coordinates mentioned.

All of this means we can rule out choices A, C, and D

Choice B means that c = 1 and this x coordinate hasn't been mentioned yet. So this could be a value of c that leads to a function. This is why choice B is the final answer.

3 0
3 years ago
29, 20, 36, 44, 30, 32, and 40.
tamaranim1 [39]

Answer:

can't understand the question.

7 0
3 years ago
Read 2 more answers
The axis of the sphere below is 16 units in length. What is the surface area of the sphere?.
Nataly_w [17]
There are enough information's already given in the question. Based on those information's that answer can be easily deduced.
Radius of the sphere = 8 units
Then
Surface area of the sphere = 4 *pi * r^2
                                            = 4 * pi * (8)^2
                                            = 4 * pi * 64
                                            = 256pi
I hope that this answer has come to your help.
5 0
4 years ago
Read 2 more answers
What would be the sum of the lengths of the first and second diagonals rounded to the nearest whole number?
drek231 [11]

Answer:

16.17684994

Step-by-step explanation:

First diagonal

x^2 = a^2 + b^2

x^2 = 5^2 + 6^2

x^2 = 61

x ≈ 7.810249676

Second diagonal

x^2 = a^2 + b^2

x^2 = 7.810249676^2 + 3^2

x^2 = 70

x ≈ 8.366600265

Sum of both diagonals

8.366600265 + 7.810249676

= 16.17684994

6 0
3 years ago
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