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Paladinen [302]
3 years ago
14

The quotient of nine times a number and seven ?

Mathematics
1 answer:
IRISSAK [1]3 years ago
7 0
9/7n is the answer i am pretty sure
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Michael has 12% of his paycheck
Advocard [28]

Answer:

259.80 dollars was deposited from his last pay check and he will have saved 6235.20 dollars in total

Step-by-step explanation:

3 0
2 years ago
What function was used to make that pattern​
Semenov [28]

Answer:

B

Step-by-step explanation:

The differences in the terms of f(x) are + 3, + 5, + 7

Since the differences are not constant the relationship is not linear

Note the differences in the differences are + 2, + 2,

The second differences are constant indicating a quadratic relationship

Note the relationship between x and f(x)

x = 1 → 1² = 1 ← require to add 5, that is 1 + 5 = 6 ← value of f(x)

x = 2 → 2²  = 4 ← require to add 5, that is 4 + 5 = 9 ← value of f(x)

x = 3 → 3² = 9 ← require to add 5, that is 9 + 5 = 14 ← value of f(x)

x = 4 → 4² = 16 ← require to add 5, that is 16 + 5 = 21 ← value of f(x)

Thus f(x) = x² + 5 → B

3 0
2 years ago
A sheet of plastic has an area of 35 square cm. If the sheet is 5 cm thick, what is the volume?
Andre45 [30]

Answer:

175 cm³

Step-by-step explanation:

Volume = área * thick

Volume = 35cm² * 5cn

Volume = 175 cm³

3 0
2 years ago
Read 2 more answers
What number does stand for in this equation? 6x3=(x5)-(x2)
MissTica

Answer:

the answer is 6

Step-by-step explanation:

6×3=18

So 6×5=30, 6×2=12

30-12=18

18=18

3 0
3 years ago
How many complex zeros does the polynomial function have? <br><br> F(x)=2x^4 +5x^3 - x^2 +6x-1
klio [65]

Answer:

Two complex roots.

Step-by-step explanation:

F(x)=2x^4 +5x^3 - x^2 +6x-1

is a polynomial in x of degree 4.

Hence F(x) has 4 roots.  There can be 0 or 2 or 4 complex roots to this polynomial since complex roots occur in conjugate pairs.

Use remainder theorem to find the roots of the polynomial.

F(0) = -1 and F(1) = 2+5-1+6-1 = 11>0

There is a change of sign in F from 0 to 1

Thus there is a real root between 0 and 1.

Similarly by trial and error let us find other real root.

F(-3) = -1 and F(-4) = 94

SInce there is a change of sign, from -4 to -3 there exists a real root between -3 and -4.

Other two roots are complex roots since no other place F changes its sign

7 0
3 years ago
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