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Bess [88]
3 years ago
9

Answer the question on the attachement

Mathematics
1 answer:
Mama L [17]3 years ago
7 0
Answer: 6 cups of water
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Find the lengths of the segments with variable expressions.
Luba_88 [7]

Answer:

Step-by-step explanation:

By the trapezoid midsegment theorem,

2x = (x-6) + (2x-8)

2x = x - 6 + 2x - 8

2x = 3x - 14

x = 14

So we know AD = 8, EF = 14, and BC = 20

8 0
2 years ago
On the first day of a trip, the Brenner family hikes 2.8 miles. On the second day, they hike 1.25 along a trail. They take a bre
Vadim26 [7]
They hiked more on the 2nd day because they are retracing their steps.
8 0
3 years ago
What is the distance between (-3, 4) and (4, 4)
svetoff [14.1K]

Answer:

7 units

Step-by-step explanation:

\sqrt{|-3-4|^{2}-|4-4|^{2}}

=7

3 0
3 years ago
Read 2 more answers
I will give brainliest to the first to answer
bonufazy [111]

Answer:

2/6 = 1/3

8/1 = 8

2/4 = 4/8

2/8 = 1/4

4/4 = 1

Step-by-step explanation:

2/2 = 1 and 6/2 = 3 so that would make the equivalent fraction 1/3

for 8/1 it is the same as just 8

2*2 = 4 and 4*2 = 8 so that would make the equivalent fraction 4/8

the same goes for 2/8 which is 1/4

and 4/4 is just 1  

PLEASE RATE!! I hope this helps!!

If you have any questions comment below

5 0
2 years ago
Read 2 more answers
Suppose that S is the set of successful students in a classroom, and that F stands for the set of freshmen students in that clas
lora16 [44]

Answer:

b) 24

Step-by-step explanation:

We solve building the Venn's diagram of these sets.

We have that n(S) is the number of succesful students in a classroom.

n(F) is the number of freshmen student in that classroom.

We have that:

n(S) = n(s) + n(S \cap F)

In which n(s) are those who are succeful but not freshmen and n(S \cap F) are those who are succesful and freshmen.

By the same logic, we also have that:

n(F) = n(f) + n(S \cap F)

The union is:

n(S \cup F) = n(s) + n(f) + n(S \cap F)

In which

n(S \cup F) = 58

n(s) = n(S) - n(S \cap F) = 54 - n(S \cap F)

n(f) = n(F) - n(S \cap F) = 28 - n(S \cap F)

So

n(S \cup F) = n(s) + n(f) + n(S \cap F)

58 = 54 - n(S \cap F) + 28 - n(S \cap F) + n(S \cap F)

n(S \cap F) = 24

So the correct answer is:

b) 24

3 0
3 years ago
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