Question

PLZ HELP ASAP WILL MARK BRAINLIEST

Answer 1

Answer:

72$\sqrt{3}$

Step-by-step explanation:

The area (A) of a rhombus is calculated as

A = $\frac{1}{2}$ × d₁ × d₂ (d₁ and d₂ are the diagonals )

The diagonals bisect each other at right angles

d₁ = 2 × 6 = 12

Use the tangent ration in the upper left right triangle and the exact value

tan60° = $\sqrt{3}$

tan60° = $\frac{opposite}{adjacent}$ = $\frac{opp}{6}$ = $\sqrt{3}$ ( multiply both sides by 6 )

opp = 6$\sqrt{3}$ , then

d₂ = 2 × 6$\sqrt{3}$ = 12$\sqrt{3}$

Thus

A = $\frac{1}{2}$ × 12 × 12$\sqrt{3}$ = 6 × 12$\sqrt{3}$ = 72$\sqrt{3}$