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Stells [14]
3 years ago
15

PLZ HELP ASAP WILL MARK BRAINLIEST

Mathematics
1 answer:
RSB [31]3 years ago
3 0

Answer:

72\sqrt{3}

Step-by-step explanation:

The area (A) of a rhombus is calculated as

A = \frac{1}{2} × d₁ × d₂ (d₁ and d₂ are the diagonals )

The diagonals bisect each other at right angles

d₁ = 2 × 6 = 12

Use the tangent ration in the upper left right triangle and the exact value

tan60° = \sqrt{3}

tan60° = \frac{opposite}{adjacent} = \frac{opp}{6} = \sqrt{3} ( multiply both sides by 6 )

opp = 6\sqrt{3} , then

d₂ = 2 × 6\sqrt{3} = 12\sqrt{3}

Thus

A = \frac{1}{2} × 12 × 12\sqrt{3} = 6 × 12\sqrt{3} = 72\sqrt{3}

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The sum of 3 times the value of x and 2 is equal to 4 less than 5 times the value x. Which equation can be used to find the valu
Komok [63]

Answer:

Write the written problem into an equation to get:

3x +2 = 5x -4

To solve:

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Divide both sides by 2:

x = 6/2

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Step-by-step explanation:

6 0
3 years ago
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The area of a rectangle with width x and length 6x and 6x^2. What does the coefficient 6 mean in terms of the problem?
sveta [45]

Answer:

The coefficient 6 in 6x means 6(x) or 6 multiplied by x 6 times.

Step-by-step explanation:

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Hope this helps! If you have any other questions please don't hesitate to ask me or your teacher so you can be sure to master the subject. :)

6 0
3 years ago
HELP PLEASE!
olasank [31]

Answer        

Find out the Area of a triangle .

To proof  

Formula

Area of Triangle

= \frac{1}{2}\times( {x_1(y_{2}-y_{3}) +x_{2}(y_{3} - y_{1})+x_{3}(y_{1}-y_{2})})

Now vertices are D(3, 3) , E(3, −1) , and F(−2, −5) .

= \frac{1}{2} (3\times(-1 +5) + 3\times(-5-3)-2\times(3+1))

Solving the above

= \frac{1}{2}(3\times4+3\times-8 -2\times4)

=\frac{1}{2} (12-24-8)\\ =\frac{1}{2} (-32+12)\\=\frac{1}{2} (-20)

= -10 units²

(Neglected the negative sign as area cannot be negative.)

= 10 units ²

Area of  a triangle is 10 units ²

Hence proved

6 0
3 years ago
Pls help! 16 points:)
kenny6666 [7]

Answer: 52 degrees

Step-by-step explanation:

most likley like if correct

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