Answer:
period
Step-by-step explanation:
The attached graph shows a period of the function. Its amplitude is 1/4 (vertical distance from centerline to peak). Its period is 4π (horizontal distance from peak to peak). Its frequency is the reciprocal of the period, so would be 1/(4π).
The value 4π is the period of the function.
Let , side lawn is a.
Area of boundary is :

Now, total cost is given by :

Area left is :

Price to empty space with turfs is :

Therefore, the cost of covering the empty space with turfs at the rate of Rs 20 per sq. metre is Rs 262500.
Hence, this is the required solution.
The points have to have the coordinate y=4 to be on the y=4 line
only the (1, 4) point matches this, so yes it is a solution, all others not and are therefore no
Answer:
Step-by-step explanation:
The answer is 33.4